Page 1002 - Industrial Power Engineering and Applications Handbook
P. 1002

An  isolated phase bus system  31/947






                                                                             t/ d
                                                                             0.01 1
                                                                             4


                                                                             0.01







                            5                                                0.008
                            a!




                                                                             0.006


                                                                             0.0046
                             I
                                                                             0.004

                           1.005                                             0.002
                                                  Jm -
                                  0  50  100  150  200  250  300 350  400  450  500 550  600


                                                 &,  in .u ST per foot
                                    Note  Figure 28.13(b) in RllOOO rn is redrawn in pR/ft.

                              Figure 31.17  Curves for skin effect for isolated tubular conductors


         :.  skin effect ratio = 1.005                 :.  Total heat generated (within the enclosure)
         :.  W2 = (0.98 x 20 000)'  x 0.354 x  1 0-6 x  1.005   = 149.22 + 136.67 + 512.98
             = 136.67 W/ft                                      = 798.87 wift
        (b) By solar radiation (W,)
                                                       Suitability of the conductor
        W,  = k,  . G . A Wlft
                                                       Heat dissipation by the conductor
        where
        k,  = 0.65                                     (1) by Radiation
         G = 1100 W/m2 (for tropical areas)
          -    1100   WlfP                                  36 9
             3.28 x 3.28                               W,  = -. 10''   e.A,[T:  - Ti]Wlff
          = 102.24 W/ftz
                      *
         A =  0.5 x ___ ft'  (assuming only the upper 50% surface   where
                                                           e = 0.85 (conductor is painted matt black with
                 2223.1
                  144
                         to be subjected to direct solar radia-   nonmagnetic paint)
                         tion)            ]               A,  = 141 1.49 square inches
         ..   W,  =  0.65 x 102.24 x  ( 0.5  ~~22~23.12   TI  = 105 + 273
                                                            = 378°C
                                                          T2 = 95 + 273
                 = 512.98  Wlft                             = 368
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