Page 528 - Modelling in Transport Phenomena A Conceptual Approach
P. 528

508                    APPENDIX A.  MATHEMATICAL PRELIMwARTEs


             where
                                                     (0 is in degrees)       (A. 7- 15)

             In Eqs.  (A.7-12)-(A.7-14) the upper sign applies if N  is positive, the lower  sign
             applies if N  is negative.


             Example A.4  Cubic equations of state are frequently used in thermodynamics to
             describe the PVT behavior of liquids and vapors.  These equations are expressed in
             the form
                                          RT
                                     p=--            a(T)                    (A. 7- 16)
                                         P-b     Va+pV+y
             where the terms a, p, y, and a(T) for diflerent types of equations of state are given
             by



               vander Waals   2      0     0         lZ

               Redlich-Kwong  2      b     0       a/@-
              Peng-Robinson  2      2b     -b2      a(T)


              When Eq.  (A.7-16) has  three real  roots, the  largest  and  the smallest  roots cor-
             respond  to  the molar  volumes  of the vapor  and  liquid  phases,  respectively.  The
             intermediate root has no physical meaning.
                Predict the density  of saturated methanol vapor at  10.84 atm and  140 "C using
             the van der  Waals equation of state.  The coeficients a and  b are given as
                                     a = 9.3424 m6. atm/ kmo12
                                      b = 0.0658 m3/ kmol

             The experimental value of the density of saturated methanol vapor is 0.01216 g/ cm3.

             Solution

             For the van der  Waals equation of state, Eq.  (A.7-16) takes the form
                                                -    a-  ab
                                                v2+pv- - =o
                                                           P

             Substitution of the values of a, b, R, and  P into Eq.  (1) gives
                                P3 - 3.1923 V2 + 0.8618 v - 0.0567 = 0
   523   524   525   526   527   528   529   530   531   532   533