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A.8.  METHODS OF IlVTEGRATION                                       513

              If  f(x) is a monotonic function, then the value of I  is bounded  by  Imin  and
           I,,   such that

                       Monotonically increasing function   Imin = f(a)(b-a)

              f (3) =                                                       (A. 8-3)
                       Monotonically decreasing function   Imin = f(b)(b-a)
                                                      Imm = f (a)(b - a)
           In some cases, only part of the integrand may be approximated to permit analytical
           integration, i.e.,



                             I = J,” f (x)g(x) dx =                         (A.8-4)






           Example A.5  Evaluate the integral




           Solution

           Analytical  evaluation of the integral is possible and the result is

                       I  = loxzdmdx

                        - 2 (0.15 x2 - 2.4s + 32)
                        -                      dmlX=lo 552.4
                                                                =
                                  0.105                     x=o
           The same integml  can be  evaluated  appmximately  as follows:  Note  that  the inte-
           grand  is the product  of two tern and the integral can be  wdten as




           where
                               f(x) = x2  and  g(x) = 4-                        (2)

           The value of  g(x) is 1.732 and  1.414 at x = 10 and  x = 0, respectively.  Since the
           value  of g(x) does not  change  dwtically  over  the  interval  0 5 x  5 10, Eq.  (1)
           can be  expressed in the form
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