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294                              Appendix C
                                                          H(x, ε)


                                                              1






                                                         2ε/2  0   ε/2         x

                                                            H(x)
                                                              1

                                                              1
                                                              2



                                                               0                x
                             Figure C.1 The Heaviside unit step function H(x), de®ned as the limit as å ! 0of
                             H(x, å).



                             and condition (C.2) is satis®ed.
                               We next assume that the derivative ä9(x)of ä(x) with respect to x exists. If we
                             integrate the product f (x)ä9(x) by parts and note that the integrated part vanishes, we
                             obtain
                                             …                 …
                                              1                 1
                                                f (x)ä9(x)dx ˆÿ    f 9(x)ä(x)dx ˆÿf 9(0)
                                             ÿ1                 ÿ1
                             where f 9(x) is the derivative of f (x). From equations (C.5a) and (C.5d), it follows that
                                                          ä9(ÿx) ˆ ä9(x)

                                                           xä9(x) ˆÿä(x)
                               We may also evaluate the Fourier transform ä(k) of the Dirac delta function
                             ä(x ÿ x 0 )
                                                     1  … 1                  1
                                             ä(k) ˆ p   ä(x ÿ x 0 )e ÿikx  dx ˆ p  e ÿikx 0
                                                                              2ð
                                                     2ð ÿ1
                             The inverse Fourier transform then gives an integral representation of the delta
                             function
                                                      1  … 1     ikx     1  … 1  ik(xÿx 0 )
                                          ä(x ÿ x 0 ) ˆ p    ä(k)e  dk ˆ  e    dk         (C:6)
                                                                         2ð
                                                      2ð ÿ1                 ÿ1
                               The Dirac delta function may be readily generalized to three-dimensional space. If r
                             represents the position vector with components x, y, and z, then the three-dimensional
                             delta function is
                                                ä(r ÿ r 0 ) ˆ ä(x ÿ x 0 )ä(y ÿ y 0 )ä(z ÿ z 0 )
                             and possesses the property that
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