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I. The Idea of Analytic Number Theory
                        2
                        four squares becomes the statement that all of the coefficients of the
                                                                        4
                                                   4          n 2
                        power series for 1 + z + z + ··· + z + ···       are positive. How
                        one proves such a fact about the coefficients of such a power series
                        is another story, but at least one begins to see how this transition
                        from integers to analytic functions takes place. But now let’s look at
                        some addition problems that we can solve completely by the analytic
                        method.



                        Change Making

                        How many ways can one make change of a dollar? The answer is
                        293, but the problem is both too hard and too easy. Too hard because
                        the available coins are so many and so diverse. Too easy because it
                        concerns just one “changee,” a dollar. More fitting to our spirit is the
                        following problem: How many ways can we make change for n if the
                        coins are 1, 2, and 3? To form the appropriate generating function,
                        let us write, for |z| < 1,

                                        1
                                              1 + z + z  1+1  + z 1+1+1  + ··· ,
                                     1 − z
                                       1
                                                    2
                                              1 + z + z   2+2  + z 2+2+2  + ··· ,
                                     1 − z 2
                                       1
                                                    3
                                              1 + z + z   3+3  + z 3+3+3  + ··· ,
                                     1 − z 3
                        and multiplying these three equations to get
                                            1
                                                       3
                                               2
                                 (1 − zð( 1 − z )(1 − z )
                                                                  2
                                      (1 + z + z 1+1  + ···)(1 + z + z 2+2  + ···)
                                               3
                                      × (1 + z + z  3+3  + ···).
                        Now we ask ourselves: What happens when we multiply out the
                                                                       2
                        right-hand side? We obtain terms like z 1+1+1+1  · z · z 3+3 . On the one
                                           12


                        hand, this term is z , but, on the other hand, it is z four1 s+one2+two3 s
                        and doesn’t this exactly correspond to the method of changing the
                        amount 12 into four 1’s, one 2, and two 3’s? Yes, and in fact we
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