Page 190 - Materials Chemistry, Second Edition
P. 190

Vadose Zone Soil Remediation                                     173



              Step 5:   Calculate the mass removal rate by multiplying the flow rate
                    (from Step 1) with the adjusted concentration (from Step 4).

             Information needed for this calculation

              •  Extracted vapor flow rate, Q
              •  Extracted vapor concentration, G
              •  Overall efficiency factor relative to the theoretical removal rate, η


           Example 5.14:   Estimate the COC Removal Rate (in the
                         Presence of Free-Product Phase)
           Recently, a gasoline spill occurred at a gasoline station and caused subsur-
           face contamination. A soil-venting well (4-in. diameter) was installed at a
           site. The pressure in the extraction well is 0.9 atm, and the radius of influence
           of this soil-venting well has been determined to be 50 ft.
             Estimate the COC removal rate at the beginning of the project using the
           following information:

              •  Permeability of the formation = 1 darcy
              •  Well screen length = 20 ft
              •  Viscosity of air = 0.018 centipoise
              •  Temperature of the formation = 20°C

              Solution:
               (a)  The flow rate has been determined in Example 5.10 to be 0.216
                   m /min, or 7.6 ft /min.
                     3
                                  3
               (b)  Assuming the free-product phase is present, the saturated vapor
                   concentration corresponding to the fresh gasoline is 1,340,000
                   ppmV, or 1,343 g/m  (see Example 5.1). On the other hand, the
                                     3
                   saturated vapor concentration corresponding to the weathered
                   gasoline is 49,000 ppmV, or 226 g/m .
                                                   3
               (c)  Assuming the overall efficiency factor is equal to unity, the
                   removal rate can be found from Equation (5.9) as:

                          R removal  = [(η)(G)](Q)
                       	  	     = [(1.0)(1,343 g/m )](0.216 m /min)
                                                        3
                                               3
                       	  	     =  290 g/min = 0.64 lb/min = 920 lb/day (for the
                                  fresh gasoline)
                       	  	     = [(1.0)(226 g/m )](0.216 m /min)
                                                       3
                                              3
                       	  	     =  48.8 g/min = 0.107 lb/min = 155 lb/day (for the
                                  weathered gasoline)
   185   186   187   188   189   190   191   192   193   194   195