Page 263 - Materials Chemistry, Second Edition
P. 263

246       Practical Design Calculations for Groundwater and Soil Remediation



              •  COC concentration in the effluent liquid, C out
              •  COC concentration in influent air, G in


           Example 6.12:   Sizing an Air Stripper for Groundwater Remediation
           A packed-column air stripper is designed to reduce chloroform concentra-
           tion in the extracted groundwater. The concentration is to be reduced from
           50 mg/L to 0.05 mg/L (50 ppb). Size the air stripper by determining the air
           flow rate, cross-sectional surface area, and packing height.
             Use the following information in calculations:

              •  Henry’s constant for chloroform = 128 atm
              •  Stripping factor = 3
              •  Temperature of the water = 15°C
              •  Extracted groundwater flow rate = 120 gpm
              •  K a = 0.01/s
                  L
              •  Type of packing = Jaeger 3” Tri-packs
              •  Hydraulic loading rate = 20 gpm/ft 2
              •  Chloroform concentration in the influent air = 0

              Solution:
               (a)  As shown in Example 6.11, the dimensionless value of the
                   Henry’s constant is equal to 0.098, and the air flow rate has been
                   determined to be 493 ft /min.
                                        3
               (b)  Use Equation (6.19) to determine the required cross-sectional area:
                                        Q            120 gpm
                              =                   =           = 6ft 2
                       A stripping                          2
                                surfaceloading rate  20 gpm/ft
                   Diameter of the air stripping column = (4 × A/π) 1/2
                       = (4 × 6/π)  = 2.76 ft
                               1/2
                   So, d = 3 ft

               (c)  Use this newly found diameter to find the hydraulic loading rate:
                   Cross-sectional area of the column = πd /4 = π(3) /4 = 7.1 ft 2
                                                      2
                                                              2
                   Hydraulic loading rate to the column (Q ) = Q/A
                                                       L
                       = [(120 gpm)(ft /7.48 gal)] ÷ 7.1 ft  = 2.26 ft/min = 0.0377 ft/s
                                                   2
                                   3
               (d)  Use Equation (6.23) to determine the HTU value:
                                      L     0.0377 ft/s
                              HTU  =      =          = 3.77 ft
                                     ( Ka)   0.01/s
                                       L
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