Page 276 - Materials Chemistry, Second Edition
P. 276

Groundwater Remediation                                          259



           Example 6.18:   Determine the Required Injection
                         Pressure of Air Sparging
           Three air-sparging wells were installed into the plume of the aquifer
           described in Example 6.17. The injection air flow rate into each well is 5 ft /
                                                                             3
           min. The height of the water column above the air injection point is 10 ft. The
           aquifer matrix consists mainly of coarse sand. Determine the minimum air
           injection pressure required. Also, for the purpose of comparison, determine
           the air injection pressure if the aquifer formation is clayey.

              Solution:
               (a)  Use Equation (6.33) to convert the water-column height to pres-
                   sure units as:
                                         lb m    ft          lb f    
                                   =  62.4
               P hydrostatic  =ρg h hydrostatic    32.2   (10ft)     2  
                                         ft 3     s 2     32.2 lb m − ft/s  

                       = 624  lb f  = 4.33  lb f  = 4.33 psi
                            ft 2     in 2
                   Note: The density of water at 60°F is 62.4 lb /ft . In other words,
                                                             3
                                                          m
                       the specific weight of water is 62.4 lb /ft . The water-column
                                                          3
                                                       f
                       height of 33.9 ft at 60°F is equivalent to a pressure of 1 atm or
                       14.7 psi.
               (b)  From Table 2.2, pore radius of fine-sand media is 0.05 cm. Use
                   Equation (2.11) to determine the height of capillary rise:
                                  0.153  0.153
                                =      =      = 3.06 cm  = 0.1 ft
                              h c
                                    r    0.05
                   Use the discussion in part (a) to convert the capillary rise to the
                       capillary pressure:

                                      0.1 ft  
                                   =         (14.7 psi)  = 0.04 psi
                             P capillary    
                                      33.9 ft 
               (c)  Use Equation (6.31) to determine the minimum air injection
                   pressure:
                                                    +
                                               = 4.33 0.04  = 4.37 psig
                       P injection  = P hydrostatic  + P capillary
               (d)  If the aquifer formation is clayey, then the pore radius is 0.0005
                   cm (from Table 2.2). Use Equation (2.11) to determine the height
                   of the capillary rise:
                                  0.153  0.153
                                =      =       = 306 cm  = 10 ft
                              h c
                                    r    0.0005
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