Page 64 - A First Course In Stochastic Models
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POISSON ARRIVALS SEE TIME AVERAGES               55

                  In the same way as in Example 2.4.1, we define the random variables

                                   1    if the system is out of stock at time t,
                           I (t) =
                                   0    otherwise.
                and

                          1    if the system is out of stock when the nth demand occurs,
                    I n =
                          0    otherwise.
                The continuous-time process {I (t)} and the discrete-time process {I n } are both
                regenerative. The regeneration epochs are the demand epochs at which the stock
                on hand drops to zero. Why? Let us say that a cycle starts each time the stock on
                hand drops to zero. The system is out of stock during the time elapsed from the
                beginning of a cycle until the next inventory replenishment. This amount of time
                is exponentially distributed with mean 1/µ. The expected amount of time it takes
                to go from stock level Q to 0 equals Q/λ. Hence, with probability 1,

                           the long-run fraction of time the system is out of stock
                                     1/µ
                                =           .                                (2.4.4)
                                  1/µ + Q/λ
                To find the fraction of demand that is lost, note that the expected amount of demand
                lost in one cycle equals λ × E(amount of time the system is out of stock during
                one cycle) = λ/µ. Hence, with probability 1,

                                the long-run fraction of demand that is lost
                                         λ/µ
                                     =         .                             (2.4.5)
                                       λ/µ + Q
                Together (2.4.4) and (2.4.5) lead to this remarkable result:
                       the long-run fraction of customers finding the system out of stock
                           = the long-run fraction of time the system is out of stock.  (2.4.6)

                The relations (2.4.3) and (2.4.6) are particular instances of the property ‘Poisson
                arrivals see time averages’. Roughly stated, this property expresses that in statistical
                equilibrium the distribution of the state of the system just prior to an arrival epoch
                is the same as the distribution of the state of the system at an arbitrary epoch
                when arrivals occur according to a Poisson process. An intuitive explanation of
                the property ‘Poisson arrivals see time averages’ is that Poisson arrivals occur
                completely randomly in time; cf. Theorem 1.1.5.
                  Next we discuss the property of ‘Poisson arrivals see time averages’ in a broader
                context. For ease of presentation we use the terminology of Poisson arrivals. How-
                ever, the results below also apply to Poisson processes in other contexts. For some
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