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340                 Chapter  Nine:  Advanced  Topics


            have  some  common    properties,  as  similar  matrices  do.  How-
            ever,  whereas  similar  matrices  have the  same  eigenvalues,  this
            is not  true  of congruent  matrices.  For  example, the  matrix



                                       ( o - a )

            has  eigenvalues  2 and  —3,  but  the  congruent  matrix


                      (i!)G-°)(i                 9-('-?)


            has  eigenvalues  —2 and  3.
                 Notice  that,  although  the  eigenvalues  of these  congruent
            matrices  are  different,  the  numbers  of  positive  and  negative
            eigenvalues  are  the  same  for  each  matrix.  This  is  an  instance
            of  a  general  result.

            Theorem     9.3.5  (Sylvester's  Law  of  Inertia)
            Let  A  be  a  real  symmetric  n  x  n  matrix  and  S  an  invertible
                                           T
            n  x  n  matrix.  Then  A  and  S AS  have  the  same  numbers  of
            positive,  negative  and  zero  eigenvalues.

            Proof
            Assume   first  of  all  that  A  is  invertible;  this  is  the  essential
            case.  Recall that  by  7.3.6  it  is possible  to  write  S  in the  form
             QR  where  Q  is real  orthogonal  and  R  is real  upper  triangular
            with  positive  diagonal  entries;  this  was  a  consequence  of  the
            Gram-Schmidt     process.
                 The   idea  of  the  proof  is  to  obtain  a  continuous  chain
            of  matrices  leading  from  S  to  the  orthogonal  matrix  Q;  the
                                   T
                                               l
            point  of this  is that  Q AQ  —  Q~ AQ  certainly  has  the  same
            eigenvalues  as  A.  Define
                                 S{t)=tQ    +     {l-t)S,

            where   0  <  t  <  1.  Thus  5(0)  =  S  while  5(1)  =  Q.  Now  write
             U  =  tl  +  (1 -  t)R,  so  that  S{t)  =  QU.  Next  U  is  an  upper
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