Page 48 - ARM 64 Bit Assembly Language

Introduction 31

e. Convert 301 10 to base 2.
f. Represent 301 10 as a null-terminated ASCII string. (Write your answer in hex-
adecimal.)
g. Convert 3420 5 to base ten.
h. Convert 2314 5 to base nine.
i. Convert 116 7 to base three.
j. Convert 1294 11 to base 5.
1.8. Given the following binary string:
01001001 01110011 01101110 00100111 01110100 00100000 01000001 01110011
01110011 01100101 01101101 01100010 01101100 01111001 00100000 01000110
01110101 01101110 00111111 00000000
a. Convert it to a hexadecimal string.
b. Convert the first four bytes to a string of base ten numbers.
c. Convert the first (little-endian) halfword to base ten.
d. Convert the first (big-endian) halfword to base ten.
e. If this string of bytes were sent to an ASCII printer or terminal, what would be
printed?
1.9. The number 1,234,567 is stored as a 32-bit word starting at address F0439000 16 .Show
the address and contents of each byte of the 32-bit word on a
a. little-endian system.
b. big-endian system.
1.10. Really good assembly programmers can convert small numbers between binary, hex-
adecimal, and decimal in their heads. Without referring to any tables or using a calcu-
lator or pencil, fill in the blanks in the following table:
Binary Decimal Hexadecimal
5

1010
C
23
0101101
4B
1.11. UTF-8 is often referred to as Unicode. Why is this not correct?
1.12. What are the differences between a CPU register and a memory location?
1.13. The ISO/IEC 10646 standard defines 1,112,064 code points (glyphs). Each code point
could be encoded using 24 bits, or three bytes. The UTF-8 encoding uses up to four
bytes to encode a code point. Give three reasons why UTF-8 is preferred over a simple
3-byte per code point encoding.