Page 169 - Advanced Design Examples of Seismic Retrofit of Structures
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Example of an RC Building Retrofitted by RC Shear Walls Chapter  3 161


                  41-13 [8], the upper-bound value of the effective length equal to the total
                  height of the shear wall was taken into account for walls P5 and P6.
              (E) In order to determine the m x and m y for each story, the procedure below
                  was followed:
                  – Determination of the shear force per length (q) assuming the cantilever
                    action of the shear wall based on the flexural capacity of the wall in
                    story  2 from Step D.
                  – Determination of the shear force at each story based on multiplication
                    of q into the total height of the story.
                  – Determination of the m-factors based on Table 3.14.
              (F) Checking satisfaction of Eq. (3.9). If not satisfied, steel plates are attached
                  to the walls in order to improve their flexural capacity.

             As an example, the calculations in this part are presented for shear wall P1 at
             story  2.
             (A) Forces and moments based on the expected values of concrete and steel
                 characteristics for deformation-controlled actions.
             P UD (ton)  V UD x  (ton)  V UD y  (ton)  T (ton. m)  M UD x  (ton. m)  M UD y  (ton. m)
             1703      529       368      1300       23,395       2093





               TABLE 3.14 m-Factors for Linear Procedures for RC Shear Walls [8]
                                                       Performance Level
                                                          Component Type
               Conditions                               Primary    Secondary

               A s  A f y + P       Confined
                              V
                    0
                    s
                              p ffiffiffiffi
                 t w l w f c 0  t w l w  f c 0  Boundary  IO  LS  CP  LS  CP
                0.1         4       Yes          2     4    6     6     8
                0.1         6       Yes          2     3    4     4     6
                0.25        4       Yes          1.5   3    4     4     6
                0.25        6       Yes          1.25  2    2.5   2.5   4
                0.1         4       No           2     2.5  4     4     6
                0.1         6       No           1.5   2    2.5   2.5   4
                0.25        4       No           1.25  1.5  2     2     3
                0.25        6       No           1.25  1.5  1.75  1.75  2
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