Page 257 - Advanced Linear Algebra
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Structure Theory for Normal Operators  241



            Proof. We  leave  the  proof of part 1) to the reader. For part 2), a
            unitary/orthogonal  map  is injective and since  =   is finite-dimensional, it is
            bijective. Moreover, for a bijective linear map  , we have


                                         is an isometry ¯ º #Á $» ~ º#Á $»  for all #Á $  =
                                          i
                                   ¯ º#Á   $» ~ º#Á $»  for all #Á $  =
                                   ¯     ~  i
                                        ¯  i    ~  c
                                   ¯    is unitary/orthogonal
            For part 3), suppose that   is unitary/orthogonal and that  E  ~¸" Á Ã Á " ¹  is an



            orthonormal basis for  . Then
                              =

                                 º " Á " »~º" Á " »~            Á


                                                                    E
            and so  E  is an orthonormal basis for  . Conversely, suppose that   and  E
                                            =
            are orthonormal bases for  . Then
                                 =
                                               ~ º" Á " »
                                 º" Á " » ~              Á
            which  implies  that  º #Á $» ~ º#Á$»   for all  #Á$  =   and so      is


            unitary/orthogonal.



            For part 4), if   is unitary and  #~ # , then
                                       #Á
                              º#Á #» ~ º    #» ~ º  #Á   #» ~ º#Á #»
            and so (( ~              ~     , which implies that (( ~     .    …
            We  also  have the following theorem concerning unitary  and orthogonal)
                                                              (
            matrices.
            Theorem 10.13 Let   be an   d    matrix over -~ d   or -~ s  .
                            (
            1   The following are equivalent:
             )
               a   (  is unitary/orthogonal.
                )
                )
               b   The columns of   form an orthonormal set in  -    .
                                (
               c   The rows of   form an orthonormal set in  -    .
                )
                             (
            2   If   is unitary, then  (  ²(³ ~   . If   is orthogonal, then det ²(³ ~ f  .
             )
                                      (det
                 (
                                             (
                           (
            Proof. The matrix   is unitary if and only if  (  (  i  ~  0  , which is equivalent to
            the  rows of  (   being orthonormal. Similarly,  (   is unitary if and only if
            (( ~ 0, which is equivalent to the columns of  ( being orthonormal. As for
             i
            part 2),
                                           i
                     i
                  (( ~ 0    ¬    det ²(³det ²( ³ ~    ¬  det ²(³det ²(³ ~
            from which the result follows.…
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