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Metric Vector Spaces: The Theory of Bilinear Forms  275



                                         <
            3   ;  )   is a nonsingular extension of   and
                                dim²;³ ~  dim²<³ b  dim²rad ²<³³

            Thus, any two nonsingular completions of   are isometric.
                                              <
            Proof.  If  < ?  =    where  ?  is nonsingular, then we may apply Theorem
            11.10 to   as a subspace of  , to obtain a hyperbolic extension A  p  >   of  <
                   <
                                    ?
            for which
                                     <‹ A  p > ‹ ?
            Thus, every nonsingular extension of   contains a hyperbolic extension of  .
                                                                          <
                                           <
            Moreover, all hyperbolic extensions of   have the same dimension:
                                            <
                            dim ²  p>  >  ³  ~  dim <  ²  ³  b  dim rad ²  <  ³  ³
                                                     ²
            and so no hyperbolic extension of   is properly contained in another hyperbolic
                                        <
            extension  of  <  . This proves that 1)–3) are equivalent. The final statement
            follows  from  the fact that hyperbolic spaces of the same dimension are
            isometric.…
            Extending Isometries to Nonsingular Completions

            Let  =    and  =  Z  be isometric nonsingular metric vector spaces and let
            <~ rad ²<³ p >   be a subspace of   = , with nonsingular completion
            <~ >  p > .

            If        ¢< ¦ <  is an isometry, then it is a  simple  matter  to  extend    to  an

            isometry   from  <      onto a  nonsingular  completion of     <  . To see this, let
            ²" Á' ÁÃÁ" Á' ³ be a hyperbolic basis for  . Since >  ²" Á ÃÁ" ³ is a basis for






            rad²<³, it follows that  ² " Á Ã Á " ³ is a basis for  rad² <³.




            Hence, we can hyperbolically extend      <~ rad    ² > ³ p >   to get

                                           ><~  Z  p >
                                                                    ÁÃÁ " Á% ³
            where >  Z  has hyperbolic basis       ² " Á%             . To extend  , simply set
                    for all    ~  ÁÃÁ .
             ' ~ %
            Theorem 11.12 Let   and =  Z  be isometric nonsingular metric vector spaces
                             =
            and let    be a subspace of  , with nonsingular completion  . Any isometry
                   <
                                                               <
                                    =
                    ¢< ¦ < can be extended to an isometry from   <  onto a nonsingular
            completion of  < .…
            The Witt Theorems: A Preview
            There are two important theorems that are quite easy to prove in the case of real
            inner product spaces, but require more work in the case of metric vector spaces
            in general. Let   and  =  Z  be isometric nonsingular metric vector spaces over a
                         =
            field  . We assume that char ²  -  ³  £      if   is orthogonal.
                -
                                            =
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