Page 312 - Advanced Linear Algebra
P. 312

296    Advanced Linear Algebra



            We can improve upon the preceding decomposition by noticing that if "<   is
            isotropic,  then  Theorem 11.10 implies that  span²"³  can be “captured” in a
            hyperbolic plane /~ span ²"Á %³ . Then we can write
                                  =~ / p /  ž <  p rad ²= ³

            where  /  ž <    is  the  orthogonal complement of  /   in  <   and has “one fewer”
            isotropic vector. In order to generalize this  process, we first discuss maximal
            totally degenerate subspaces.
            Maximal Totally Degenerate Subspaces
            Let   be a nonsingular orthogonal geometry over a field  , with char ²  -  ³  £  .
               =
                                                           -
            Suppose  that  <    and  <  Z   are maximal totally degenerate subspaces of  =  . We
                                   Z
                                                         Z
            claim that dim²<³ ~  dim²< ³ . For if dim²<³   dim²< ³ , then there is a vector
            space isomorphism       ¢< ¦ < ‹ < Z , which is also an isometry, since   and
                                                                       <
              Z
            <  are totally degenerate. Thus, Witt's extension theorem implies the existence
                                                                 Z
            of an isometry         that extends  . In particular,      ¢= ¦ =  c  ²< ³   is  a  totally
            degenerate  space  that  contains  <   and so    c  ²  <  Z ³  ~  <  , which shows that
                          Z
            dim²<³ ~  dim²< ³.
            Theorem 11.36 Let   be a nonsingular orthogonal geometry over a field  ,
                                                                           -
                             =
            with char²-³ £   .
             )
            1   All maximal totally degenerate subspaces of   have the same dimension,
                                                     =
               which is called the Witt index  of   and is denoted by  ²  $  =  . ³
                                           =
             )
                                            =
            2   Any totally degenerate subspace of   of dimension  ²  $  =  ³   is maximal.…
            Maximal Hyperbolic Subspaces
            We can prove by a similar argument that all maximal hyperbolic subspaces of =
            have the same dimension. Let
                                   >    ~ / pÄp/

            and
                                   A    ~ 2 pÄp2

            be maximal hyperbolic subspaces of   and suppose that  /     ~  ²  "     Á  #    span  ³   and
                                          =
            2~ span ²% Á & ³       . We may assume that dim ² ³  dim>  ² ³.A

            The linear map  > ¦ ¢  A  defined by
                                               "~ % Á #~ &

            is clearly an isometry from   to  >     . Thus, Witt's extension theorem implies the
                                  >
            existence of an isometry      that extends  . In particular,     ¢= ¦ =  c  ² ³  is a
                                                                       A
                                                                          A
            hyperbolic space that contains   and so    c   A  > ²³ ~  . It follows that dim ²³
                                      >
            ~     ² dim > .
                    ³
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