Page 366 - Advanced Linear Algebra
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350    Advanced Linear Algebra



                                                          /
            Of course, if  ¢ / ¦ -  is a bounded linear functional on  , then
                                              (   ( ²%³
                                       ~ sup
                                     ))
                                                %
                                           %£   ))
            The  set  of all bounded linear functionals on a Hilbert space  /  is called the
            continuous dual space, or   conjugate space, of /   and denoted by /  i . Note
            that this differs from the  algebraic  dual of  / , which is the set of all linear
            functionals on  / . In the finite-dimensional case, however, since all linear
                                                                (
                                        )
            functionals are bounded  exercise , the two concepts  agree.  Unfortunately,
                                 (
            there is no universal agreement on the notation for the algebraic dual versus the
            continuous dual. Since we will discuss only the continuous dual in this section,
            no confusion should arise.³
            The following theorem gives some simple reformulations of the definition  of
            norm.

                                       be a bounded linear transformation.
            Theorem 13.30 Let  ¢/ ¦ /
            1) )) ~      ) % sup     )
                     ))%~
            2) )) ~      ) % sup     )
                     ))%
             )
            3   )) ~         s  “  ) %    ¸ inf  )      ) )  for all    %  /  ¹  …
                                        %
            The following theorem explains the importance of  bounded  linear
            transformations.

                                        be a linear transformation. The following are
            Theorem 13.31 Let  ¢/ ¦ /
            equivalent:
             )
            1      is bounded
             )
            2      is continuous at any point % /

             )
            3      is continuous.
            Proof. Suppose that   is bounded. Then

                        )        )   )  %c %    ²%  )   ~  ) c%    )  )³   %c%    )    ¦
                                                    )
                                                                  )
                                                             )
            as %¦%    . Hence,   is continuous at %       . Thus, 1  implies 2 . If 2  holds, then
            for any & / , we have
                          )       )   )  %c & ~     ²% c& b%          ) ³c ²% ³ ¦

            as % ¦ & , since   is continuous at %     and % c& b% ¦ %        as & ¦ % . Hence,
                                                                )
                                       )
            is continuous at any & /  and 3  holds. Finally, suppose that 3  holds. Thus,
            is continuous at   and so there exists a  €         such that

                                   ))%    ¬  ) %

                                                )
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