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Tensor Products   367



            Bilinearity on <d =   Equals Linearity on <n =
            The universal property for bilinearity says that to each  bilinear   function
             ¢ <d = ¦ > , there corresponds a unique  linear  function    ¢ <n = ¦ > ,
            called the mediating morphism for  . Thus, we can define  the  mediating

            morphism map
                                               B¢ hom
                                   ²<Á =Â > ³ ¦ ²< n =Á > ³
            by setting       ~  . In other words,     is the unique linear map for which

                                   ²  ³²" n #³ ~  ²"Á #³

            Observe that   is itself linear, since if  Á   hom ²<Á= Â> ³ , then

                  ´  ² ³ b   ² ³µ²" n #³ ~   ²"Á #³ b   ²"Á #³ ~ ²   b   ³²"Á #³


            and so  ² ³ b   ² ³  is the mediating morphism for    b    , that is,


                                  ² ³ b   ² ³ ~ ²   b   ³



            Also,      is surjective, since  if     ¢< n = ¦ >   is any linear map, then
             ~    k !¢ < d = ¦ >   is  bilinear  and has mediating morphism  , that is,

                   ~ . Finally,   is injective, for if       ~  , then     ~   k ! ~  . We have

            established the following result.
                                                          -
            Theorem 14.4 Let  ,   and >  be vector spaces over  . Then the mediating
                            <=
            morphism map       ²<Á =Â > ³ ¦  B¢ hom    , where    ²< n =Á > ³     is  the  unique
            linear map satisfying  ~   k ! , is an isomorphism and so

                                               B¢ hom
                                   ²<Á = > ³ š ²< n =Á > ³                …
            When Is a Tensor Product Zero?
            Armed with the universal property of bilinearity, we can now discuss some of
            the basic properties of tensor products. Let us first consider the  question  of
                                 is zero.
            when a tensor    "n #
            The bilinearity of the tensor product gives
                              n# ~ ² b ³ n# ~   n#b n#

            and so  n# ~   . Similarly, " n  ~   . Now suppose that
                                        "n # ~


            where we may assume that none of the vectors  "   and  #      are  .  Let

             ¢ <d = ¦ >   be a bilinear map and let    ¢ <n = ¦ >  be its mediating
            morphism, that is,   k! ~   . Then
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