Page 482 - Advanced Linear Algebra
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466    Advanced Linear Algebra




            Theorem 18.11 (Wedderburn's theorem )  If   is a finite division algebra, then
                                                 +
            + is a field.
            Proof. We must show that   is commutative. Let  .  ~  +  i  be the multiplicative
                                  +
            group of all nonzero elements of  . The class equation is
                                      +
                                         i
                                                   i

                              (  i  (+~ A²+ ³ b   ²+ ¢ *² ³³
                                          (
                                    (
            where the sum is taken over one representative   from each conjugacy class of

            size greater than  . If we assume for the purposes of contradiction that   is not
                                                                      +

                                     i
            commutative, that is, that A²+ ³ £ + i  , then the sum on the far right is not an
            empty sum and so  (  i  (*² ³  (   i  ( +   for some   + i  .


            The  sets  A²+³   and  *² ³   are subalgebras of  +  and, in fact,  A²+³  is a
            commutative  division algebra; that is, a field. Let  (  (A²+³ ~' ‚  . Since
            A²+³ ‹ *² ³, we may view  *² ³ and  + as vector spaces over  A²+³ and so



                               (     (*² ³ ~ '  ² ³  ( and  + ~ '
                                                    (

            for integers   ² ³  . The class equation now gives

                                                   'c

                               'c   ~ ' c   b
                                                  '   ² ³  c


                                               ² ³
            and since  '   ² ³  c     “  '     c     , it follows that  ²     ³  “  .


            If  8²%³  is the  th cyclotomic polynomial, then  8²'³  divides  ' c   . But



            8²'³ also divides each summand on the far right above, since its roots are not


            roots of  '   ² ³  c     . It follows that  8  ²  '  ³    “  '  c     . On the other hand,
                                    8²'³ ~    ²' c ³


                                            
                                            +
            and since       +   implies that  '  (    c    (  €  '  c     , we have a contradiction. Hence
                i
            A²+ ³ ~ +  and  + is commutative, that is,  + is a field.…
                      i
            Finite-Dimensional Real Division Algebras
            We now consider the finite-dimensional division algebras over the real field  .
                                                                           s
            In 1877, Frobenius proved that there are only three such division algebras.
            Theorem 18.12 (Frobenius, 1877 )  If   is a finite-dimensional division algbera
                                           +
            over , then
                s
                               +~ Á     +~ d       +~ i or
                                   s
            Proof. Note first that the minimal polynomial   ²%³  of  any     +   is  either


            linear, in which case   s  or irreducible quadratic   ²%³ ~ % b  % b    with


             c      . Completing the square gives
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