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172    CHAPTER 6  Vectors and Vector Spaces

                                 But each time we form such a list by replacing a spanning set vector with a basis vector, we
                                 obtain a new set of vectors that spans S. This would make G k+1 a linear combination of the first
                                 k basis vectors, and then these basis vectors would be linearly dependent, a contradiction.
                                    This proves that this possibility cannot occur, leaving the first possibility, and t ≤ k.


                                                                                                     n
                                    This theorem has a profound consequence—all bases for a given subspace of R have the
                                 same number of vectors in them.

                           COROLLARY 6.1

                                                                                   n
                                 Let G 1 ,··· ,G m and H 1 ,··· ,H k be bases for a subspace S of R . Then m = k.
                                 Proof  Each basis is a spanning set, so two applications of Theorem 6.4 gives us m ≤k and also
                                 k ≤ m.



                                                                               n
                                   The number of vectors in a basis for a subspace S of R is called the dimension of S.For
                                            n
                                                                             3
                                   example, R has dimension n, and the subspace of R in Example 6.17 has dimension 2.

                                                                            n
                                    Now suppose S is a k-dimensional subspace of R , and v 1 ,v 2 ,··· ,v k form a basis for S.If
                                 X is in S, then there are numbers c 1 ,c 2 ,··· ,c k such that
                                                                                 k

                                                       X = c 1 v 1 + c 2 v 2 + ··· + c k v k =  c j v k .
                                                                                j=1


                                   The numbers c 1 ,··· ,c k are called the coordinates of X with respect to this basis. These
                                   coordinates are unique to X and to this basis.



                                 For, if

                                                              X = d 1 v 1 + ··· + d k v k
                                 then
                                                                                    k

                                              X − X = O = (c 1 − d 1 )v 1 + ··· + (c k − d k )v k =  (c j − d j )v j .
                                                                                    j=1
                                 Since the vectors v 1 ,··· ,v k are linearly independent, each c j − d j = 0, and therefore each
                                 c j = d j .
                                    A nontrivial subspace of R has many bases, and each n-vector X has unique coordinates
                                                          n
                                 with respect to each basis. However, on a practical level, some bases are more convenient to work
                                 with in the sense that coordinates of vectors with respect to these bases are easier to determine.
                                                                4
                                 To illustrate, let S be the subspace of R consisting of all vectors < x, y,0,0>, with x and y any
                                 real numbers.
                                    This is a two-dimensional subspace with e 1 =< 1,0,0,0 > and e 2 =< 0,1,0,0 > forming a
                                 basis B 1 for S. The vectors

                                                     w 1 =< 2,−6,0,0 > and w 2 =< 2,4,0,0 >




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