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9.3 Some Special Types of Matrices  289


                                        is skew-hermitian because
                                                                   ⎛               ⎞
                                                                      0   −8i  −2i
                                                                                         t
                                                                S = −8i    0   −4i ⎠ =−S .
                                                                   ⎝
                                                                     −2i  −4i   0
                                           We want to derive a result about eigenvalues of hermitian and skew-hermitian matrices.
                                        For this we need the following conclusions about the numerator of the general expression for
                                        eigenvalues in Lemma 9.1.


                                  LEMMA 9.2

                                        Let
                                                                             ⎛ ⎞
                                                                               z 1
                                                                               z 2
                                                                             ⎜ ⎟
                                                                             ⎜ ⎟
                                                                          Z = ⎜ . ⎟
                                                                                .
                                                                             ⎝ . ⎠
                                                                               z n
                                        be a complex n × 1 matrix. Then
                                                                      t
                                           1. If H is n × n hermitian, then Z HZ is real.
                                                                           t
                                           2. If S is n × n skew-hermitian, then Z HZ is pure imaginary.
                                                                                                  t
                                        Proof of Lemma 9.3 For condition (1), suppose H is hermitian, so that H = H. Then
                                                                    t
                                                                                      t
                                                                              t
                                                                  (Z HZ) = ((Z) )HZ = Z HZ.
                                             t
                                        But Z HZ is a 1 × 1 matrix and so equals its own transpose. Continuing from the last equation,
                                        we have
                                                                                t
                                                                                          t
                                                                                  t
                                                                        t
                                                                                     t
                                                                t
                                                                            t
                                                               Z HZ = (Z HZ) = Z H (Z) = Z HZ.
                                        This shows that
                                                                         t       t
                                                                       (Z HZ) = Z HZ.
                                              t
                                        Since Z HZ equals its own conjugate, this quantity is real.
                                                                                          t
                                           To prove condition (2), suppose S is skew-hermitian, so S =−S. By an argument like that
                                        in the proof of condition (1), we find that
                                                                         t        t
                                                                       (Z SZ) =−Z SZ
                                                  t
                                        If we write Z SZ = a + ib, then the last equation means that
                                                                       a − ib =−a − ib.
                                                                   t
                                        But then a =−a so a = 0 and Z SZ is pure imaginary. This includes the possibility of a zero
                                        eigenvalue.

                                           This lemma absorbs most of the work we need for the following result, giving us information
                                        about eigenvalues.




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                                   October 14, 2010  14:49  THM/NEIL   Page-289        27410_09_ch09_p267-294
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