Page 321 - Advanced engineering mathematics
P. 321

10.1 Linear Systems   301


                                         (t) is a fundamental matrix for this system. The general solution c 1   1 + c 2   2 can be written
                                        as  C:
                                                             3t         3t
                                                          −2e + (1 − 2t)e   c 1
                                                    C =        3t   3t
                                                              e + te        c 2
                                                               3t           3t  	       3t  	          3t
                                                          c 1 (−2e )  c 2 (1 − 2t)e  −2e       (1 − 2t)e
                                                      =       3t         3t    = c 1  3t  + c 2     3t
                                                            c 1 e     c 2 te         e            te
                                                      = c 1   1 (t) + c 2   2 (t).
                                           In an initial value problem, x 1 (t 0 ),··· , x n (t 0 ) are given. This information specifies the n × 1
                                        matrix X(t 0 ). We usually solve an initial value problem by finding the general solution of the
                                        system and then solving for the constants to find the particular solution satisfying the initial
                                        conditions. It is often convenient to use a fundamental matrix to carry out this plan.


                                 EXAMPLE 10.5

                                        Solve the initial value problem

                                                                      1  −4            −2

                                                                 X =         X;X(0) =      .
                                                                      1   5             3
                                        The general solution is  C, with   the fundamental matrix of Example 10.4. To solve the initial
                                        value problem we must choose C so that

                                                                                   −2
                                                                    X(0) =  (0)C =      .
                                                                                    3
                                        This is the algebraic system


                                                                      −2   1       −2
                                                                              C =      .
                                                                       1   0       3
                                        The solution for C is
                                                                     	 −1
                                                               −2   1    −2      01     −2     3
                                                          C =                =              =     .
                                                                1   0     3      12     3      4
                                        The unique solution of the initial value problem is
                                                                          	        3t    3t
                                                                         3     −2e − 8te
                                                              X(t) =  (t)   =     3t    3t  .
                                                                         4      3e + 4te
                                        10.1.2  The Nonhomogeneous System

                                        We will develop an analog of Theorem 2.5 for the nonhomogeneous linear system X =AX + G.

                                        The key observation is that, if   1 and   2 are any two solutions of this nonhomogeneous system,

                                        then their difference   1 −   2 is a solution of the homogeneous system X = AX. Therefore, if
                                        is a fundamental matrix for this homogeneous system, then
                                                                          1 −   2 =  K
                                        for some constant n × 1matrix K, hence
                                                                          1 =   2 +  K.

                                           We will state this result as a general theorem.




                      Copyright 2010 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).
                      Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

                                   October 14, 2010  20:32  THM/NEIL   Page-301        27410_10_ch10_p295-342
   316   317   318   319   320   321   322   323   324   325   326