Page 233 - Air and Gas Drilling Manual
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2
                                                                       2
                                                                  1 366)
                                                                  (.
                                                             
                                                .
                                                          .
                                                         53 36
                                      b =
                                                             
                                       i
                                                                  2
                                                                π
                                                                
                                             (
                                           2 322 . ) ( .
                                                         10 .
                                                                         4
                                                                     0 389)
                                                                    (.
                                                                
                                                                4
                                      b = 236 1 0 016 0389) Chapter 5: Shallow Well Drilling Applications    5-75
                                              .
                                       i
                                   The  bottomhole  temperature  is  determined  from  the  surface  geothermal
                               temperature rock formations at the surface, the geothermal gradient, and the depth of
                               the borehole.  The geothermal temperature of the rock formations near the surface is
                               assumed to be represented by the temperatures given in Table 4-1 (also see Appendix
                               D).  Thus, for a 2,000 ft surface location this  temperature is  assumed to  be 51.9˚F.
                               For this example the geothermal gradient is approximated to be 0.01˚F/ft.  Thus,  T bh
                               is
                                              o
                                      t  = 51 9 F
                                             .
                                       r
                                      T =  t + 459 67.
                                       r
                                            r
                                      T = 511 57.  o  R
                                       r
                                      T bh  =  T + 0 01 2 400.  ( ,  )
                                             r
                                                 o
                                      T bh  = 535 54 R
                                              .
                               The average temperature of this borehole is
                                            T +  T
                                      T av  =  r  bh
                                               2
                                                 o
                                      T  = 523 54 R
                                              .
                                       av
                               Equation 5-12 becomes
                                                               2  (. 0 035 ) ( , 2 400  )    . 05
                                           [
                                                                                          
                                     P  =  ( , 1 967 ) 2  + 236 1  .54 ) 2 ]  e  523 .54  − 236 1  .54 ) 2 
                                                      . (523
                                                                                 . (523
                                     ai
                                                                                        
                                                                                          
                                                    2
                                      P  = 5 421 lb/ft abs
                                            ,
                                       ai
                                            P ai
                                      p ai  =
                                            144
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