Page 48 - Air and Gas Drilling Manual
P. 48

.
                                      ρ
                                            32 2
                                              .
                                      ρ a  =  0 688  lb  − sec  2      Chapter 1: Introduction    1-25
                                            .
                                         = 0 0214
                                       a
                                                    ft  4
                                   The average velocity at this  position  is  approximately 30  ft/sec.    Using  these
                               values  in  Equation  1-1,  the  kinetic  energy  per  unit  volume  for  the  air  drilling
                               example becomes
                                      KE a  =  1  (0 0214 ) (30 0 .  ) 2
                                                 .
                                             2
                                                ft −  lb
                                              .
                                      KE   = 96
                                         a         3
                                                 ft
                                   The kinetic energy per unit  volume values of the two  example  flows  (drilling
                               mud and compressed air) are nearly the same at the position  in  the annulus where it
                               would  be  expected  that  the  rock  cuttings  carrying  capacity  of  the  fluids  are  a
                               minimum.  The flow kinetic energy per unit  volume of the mud  drilling  fluid does
                               not  change as the drilling  mud  flows to  the surface in  the annulus (uniform  cross-
                               sectional area).  The flow kinetic energy per unit  volume of the compressed air  on
                               the other hand increases exponentially as it  seeks atmospheric conditions at the exit
                               to the annulus.  This is because the compressed air has stored internal energy and as
                               it starts up the annulus and resistance to flow decreases (i.e.,  lower hydrostatic head)
                               this internal energy is converted to velocity.
                               References

                               1. Marcus, R. D., et al., Pneumatic Conveying of Solids, Chapman and Hall, 1990.
                               2. Singer, C., et al., A History of Technology, Vol. 4, Oxford Press, 1958.
                               3. Singer, C., et al., A History of Technology, Vol. 5, Oxford Press, 1958.

                               4. Singer, C., et al., A History of Technology, Vol. 6, Oxford Press, 1958.

                               5. Personal communication with H. J. Gruy, February 5, 1997.
                               6. API Recommended Practice for Drill Stem Design and Operating Limits, API
                                 RP7G, 16th Edition, August 1998.

                               7. Roscoe Moss Company, Handbook of Ground Water Development, Wiley, 1990.
                               8. Burghardt, M. D., Engineering Thermodynamics with Applications, Harper and
                                 Row, 1982.
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