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28  Basic elasticity


                                           Y


                                                       Q,  (360 x 1 04, ix 650 x 1 04)










                    (-290 x 1 04,


             Fig. 1.14  Mohr's circle of strain for Example 1.3.


             Now substituting in Eq. (1.35) for E,,  E, and -yrY
                                                                     1
                            &I  = 10-          +  \/(360  + 290)2 + 6502

             which gives
                                          &I  = 495 x
             Similarly, from Eq. (1.36)

                                         EII  = -425  x  IOp6
             From Eq. (1.37)
                                              650 x
                                 tan20 =
                                         360 x  lop6 + 290 x  lop6 =
             Therefore
                                          20 = 45" or 225"
             so that
                                         0 = 22.5" or 112.5"
               The values of E~, and 0 are verified using Mohr's circle of strain (Fig. 1.14). Axes
             OE and  Oy  are  set  up  and  the  points  Q1 (360 x  lop6,: x 650 x   and  Q2
             (-290  x  lop6, - 4 x 650 x  IOp6) located. The centre C of the circle is the intersection
             of Q1Q2 and the OE axis. The circle is then drawn with radius CQ1 and the points
             B(q) and A(eII) located. Finally angle QICB  = 20 and angle QICA = 20 + 7r.





             Stresses at a point on the surface of a piece of material may be determined by measur-
             ing the strains at the point, usually by electrical resistance strain gauges arranged in
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