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564  Elementary aeroelasticity

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                  Fig. 13.18  Cantilever beam of Example 13.5.

                  we obtain

                            O=C+F                                                       6)
                            O=AB+xD                                                    (ii)
                            0 = -X2BsinXL-  X2CcosXL+X2DsinhXL+X2FcoshAL               (iii)

                            0 = -X3Bcos XL + X3C sin XL + X3D cosh XL + X3F sinh AL    (iv)
                  From Eqs (i) and (ii), C = -F  and B = -D.  Thus, replacing F and D in Eqs (iii) and
                  (iv) we obtain
                                B(-  sin XL  - sinh XL) + C( - cos XL  - cosh XL) = 0   (v)
                  and

                                 B(- cos XL  - cosh XL) + C(sin XL  - sinh XL)  = 0    (vi)
                  Eliminating B and C from Eqs (v) and (vi) gives
                          (-  sin XL  - sinh XL) (sinh XL - sin XL) + (cos XL + cosh XL)2 = 0

                  Expanding  this  equation,  and  noting  that  sin2 XL + cos2 XL  = 1  and
                  cosh2 XL  - sinh’ XL  = 1, yields the frequency equation
                                            cosXLcoshXL+  1 = 0                       (vii)

                  Equation (vii) may be solved graphically or by Newton’s method. The first three roots
                  XI, X2 and X3 are given by
                                    AIL = 1.875,  X2L = 4.694,   X3L = 7.855

                  from which are found the natural frequencies corresponding to the first three normal
                  modes of vibration. The natural frequency of the rth mode (r 2 4) is obtained from
                  the approximate relationship

                                                X,L  = (r - ;)7r
                  and its shape in terms of a single arbitrary constant K, is
                                V,(z) = K,[coshX,z - cos X,z - k,(sinhX,z  - sin X,z)]
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