Page 443 - Analog and Digital Filter Design
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440 Analog and Digital Filter Design




                        2.3   Chebyshev and Cauer (elliptic).
                        2.4   Inverse Chebyshev and Cauer (elliptic).

                        2.5   Cauer filters have ripple in both passband and stopband. They are
                              used because they have a very steep skirt (almost a "brick wall"
                              response).
                        2.6   Bessel filters have a constant delay in the passband. Unfortunately,
                              they have a very shallow skirt response.
                        2.7   Component values are normalized so that one set of data (usually
                              written in a table) can be applied to any cutoff frequency or load
                              impedance by simply scaling the values.


                  Chapter 3

                        3.1   An output step followed by a smooth exponential decay.

                        3.2   -0.3  -j0.67.
                        3.3   Imaginary axis.
                        3.4   A null in the stopband; otherwise known as stopband ripple. The
                              presence of  two zeroes implies a Cauer (elliptic) or Inverse Chebyshev
                              response.
                        3.5   Butterworth poles are located on the unit circle. Each pole is
                              equidistant from the origin, and they have equal angular distance
                              between each other.
                        3.6   Chebyshev poles are located on an ellipse. The Butterworth filter pole
                              locations are shifted towards the imaginary axis (to the right) and away
                              from the real axis (up or down). The amount of  pole movement is
                              mathematically derived.



                  Chapter 4

                        4.1   An inductor value has to be increased in proportion to the load value,
                              so to denormalize for impedance we get 0.8212H x 50 = 41.06H. To
                              scale for cutoff frequency of 20 kHz, remember that we want the
                              inductor to have an impedance equivalent to a 41.06H inductor at 1
                              radian per second (which is 41.06ohms at lradls). This means that we
                              have to divide by 27cF radls, where F is the cutoff frequency. In this
                              case 2nF= 125,664radls. In summary, L = 0.8212 x R12rtF. This gives a
                              denormalized value of  327pH, which has an impedance of 41.06ohms
                              at 20 kHz.
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