Page 182 - Analytical Electrochemistry 2d Ed - Jospeh Wang
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EXAMPLES                                                        167

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            EXAMPLES

            Example 5-1  Calculate the relative error (in proton concentration) that would
            occur if the pH of a 1   10  2  M NaOH solution were measured with a pH glass
            electrode …k H;Na  ˆ 10  10 ; assuming activity coef®cient of 1.0).

            Solution  The concentration of the interfering sodium ion is 1   10 7 2  M, while
            that of the target proton is



                          ‰H Šˆ K =‰OH Šˆ 10  14 =10  2  ˆ 1   10  12 M
                            ‡
                                 w
            From equation (5.6), we thus obtain

                                                                 2
                       E   ˆ K ‡ 0:059 log‰1   10  12  ‡ 10  10   …1   10 †Š
                        cell
            The relative error in concentration is thus


                                          2
                            ‰10  10   …1   10 †=10  12 Š  100 ˆ 100%
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