Page 42 - Basic Structured Grid Generation
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Classical differential geometry of space-curves  31

                                                                     2
                                                                         2 −
                        from eqn (2.5), which may be integrated to give t = (a +c )  1 2 s and the intrinsic form

                                           s                     s                cs
                             x = a cos √         ,  y = a sin √         ,  z = √       .    (2.6)
                                                                                  2
                                                                 2
                                          2
                                         a + c 2                a + c 2          a + c 2
                                                                                        √
                                                                                          2
                                                                                               2
                          Thus the length of this curve in one complete turn about the z-axis is 2π a + c ,
                        the distance advanced in the direction of the z-axis during this turn being 2πc.
                          Differentiating eqn (2.1) with respect to t at a point P on the curve gives a vector
                                                     ˙ r = i˙x + j ˙y + k˙z,                (2.7)

                                                                                           2
                                                                                      2
                                                                                               2
                                                                               s
                        which is tangential to the curve. The magnitude of this vector is ˙ =  ˙ x +˙y +˙z ,
                        so that a unit tangent vector is
                                                  ˙ r  dr   dx   dy     dz
                                              t =   =    = i   + j  + k   .                 (2.8)
                                                  ˙ s  ds   ds    ds    ds
                          Differentiating the identity
                                                         t · t = 1
                        with respect to s gives
                                                          dt
                                                        t ·  = 0,
                                                          ds
                        which shows that the vector dt/ds is perpendicular to t. The direction of this vector at
                        a point P , given by the unit vector n, is the direction of the principal normal to the
                        curve at that point, and we write
                                                         dt
                                                           = κn,                            (2.9)
                                                         ds
                        where κ is called the curvature at that point. We usually assume that κ is a non-
                        negative function of s, although there are circumstances where it would be convenient
                        to let it take negative values in order to allow n to be a continuous vector func-
                        tion of s.Ifdt/ds = 0, which would be the case everywhere when the curve is a
                        straight line, then κ = 0, but n is not uniquely defined. The plane containing the
                        tangent and the principal normal at a point on a curve is called the osculating plane
                        at that point.

                          Introducing the shorthand notation  d  () = () ,wehave
                                                        ds
                                                          t = r
                        and





                                               t = r = ix + jy + kz = κn.                  (2.10)
                        Hence

                                                              2     2      2
                                             κ =|r |=    (x ) + (y ) + (z ) .              (2.11)
                          The Chain Rule for differentiation gives

                                                         ˙ r = r ˙s                        (2.12)
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