Page 79 - Basic Structured Grid Generation
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68  Basic Structured Grid Generation

                          Further important equations may be obtained by considering the consistency of
                        different representations of Gauss’s formula through the equations
                                                     2
                                                                      2
                                              ∂     ∂ r        ∂     ∂ r
                                                           =                ,
                                                                     α
                                                    α
                                             ∂u γ  ∂u ∂u β   ∂u β  ∂u ∂u γ
                        or
                                                 ∂     ∂a α     ∂     ∂a α
                                                           =            ,
                                                ∂u γ  ∂u β   ∂u β  ∂u γ
                        which gives
                                  ∂    µ               ∂   µ
                                                             a
                             0 =     (  a µ + b αβ N) −  (  αγ µ + b αγ N)
                                       αβ
                                 ∂u γ                 ∂u β
                                     µ       µ
                                   ∂  αβ  ∂  αγ        µ ∂a µ     ∂a µ
                                                                µ
                               =        −        a µ +   αβ  −   αγ
                                   ∂u γ    ∂u β          ∂u γ     ∂u β
                                      ∂N        ∂N      ∂b αβ  ∂b αγ
                                 +b αβ  γ  − b αγ  β  +   γ  −   β  N
                                      ∂u       ∂u      ∂u     ∂u
                                     µ       µ
                                   ∂  αβ  ∂  αγ       µ        µ
                                                   δ
                                                            δ
                               =        −      +        −   αγ    δβ  − b αβ b γδ a δµ  + b αγ b βδ a δµ  a µ
                                                   αβ δγ
                                   ∂u γ    ∂u β

                                      µ        µ       ∂b αβ  ∂b αγ
                                 +   b µγ −    αγ µβ +     −        N,
                                                 b
                                      αβ                 γ      β
                                                       ∂u     ∂u
                        using both eqns (3.121) and (3.122). Since a 1 , a 2 ,and N are an independent set of
                        vectors, it follows that we must have both
                                µ      µ
                             ∂
                                αβ   ∂  αγ   δ  µ     δ   µ          δµ         δµ
                                  −       +        −   αγ    δβ  − b αβ b γδ a  + b αγ b βδ a  = 0  (3.123)
                                             αβ δγ
                              ∂u γ   ∂u β
                        and
                                             µ        µ       ∂b αβ  ∂b αγ
                                              b µγ −    b          −      = 0             (3.124)
                                             αβ       αγ µβ +   γ       β
                                                              ∂u     ∂u
                        for all possible values of the free (unrepeated) indices.
                          We can appeal to eqn (3.64) to re-write eqn (3.123) as
                                                µ            δµ         δµ
                                              R     = b αγ b βδ a  − b αβ b γδ a          (3.125)
                                                .αβγ
                        and multiplication through by a νµ (with summation over µ), using eqn (3.65), gives
                                                 R ναβγ = b αγ b βν − b αβ b γν .         (3.126)
                          Since we know that the curvature tensor R ναβγ has only one independent component
                        R 1212 , eqns (3.126) reduce to a single equation
                                                                2
                                             R 1212 = b 11 b 22 − (b 12 ) = det(b αβ ),   (3.127)
                        and this is Gauss’s equation. It has the consequence that since R 1212 is an intrin-
                        sic quantity, derivable entirely in terms of the covariant metric tensor a αβ ,then
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