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Acids and bases                      IJ'/

                               AgCl(s) +2 Ag + (aq) + Cl - ( aq)      (5 . 2 91
                    Ag + (aq) + 2NH3 (aq)  +2 Ag(NH3) !  (aq)         (5 . 3 0)


            Net:     AgCl(s) + 2NH3(aq) +2 Ag(NH3} ! (aq) + Cl- (aq)
            For the  Lewis  base  NHiaq)  to increase  the  solubility  of AgCl(s)  -
            that  i s ,   to  drive  reaction  (5.29)  to  the  right  - it  must  interact  more
            strongly with Ag + (aq) than does water .
              A  metal  ion  combined  with  a  Lewis  base,  such  as  Ag(NH ! h
            (aq),  is called a  complex ion.  The equilibrium constant  fo  r   the forma­
             tion of a complex ion from a metal ion in aqueous solution is called the
            f o rmation  constant (Kr )  of the complex  ion.  The higher the  value  of
            Kc  the  more  stable  is  the complex  ion.  Values  of the formation  con­
            stants for some metal complex ions are given in Appendix IV.



                       5 . 1 1   Mass balance and charge balance relations
            The  ionization  of  any  weak  Br�nsted-Lowry  acid  HA  is  given  by
            Reaction (5 . 8 ),  which,  for convenience ,  we repeat here




            Also ,
                                                                      (5.32)
                                            -
             How can we calculate [HA(aq)] ,  [A  ( aq)] ,  [H30 + (aq)] and [OH - ( aq)]
            for a given initial concentration of HA in water? Since there  are four
            unknowns , we need four relationships between the unknowns .
               The  equilibrium  constants  for  Reactions  (5 . 3   l )   and  (5 . 3 2 )  provide
            two of the relationships
                                     [H30 + (aq)][A - (aq)]
                                                                      (5. 3 3)
                                 K  = �������
                                  a       [HA(aq)]
            and,
                                Kw =  [H30  + (aq)]l OH - (aq)]       (5.34)

             where  the  values of Ka and  Kw are assumed to be known.
               We can obtain a third relationship from the fact that the mass of HA
             must be conserved. Therefore, we can write
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