Page 257 - Biofuels for a More Sustainable Future
P. 257

232   Biofuels for a More Sustainable Future


                                             1  1
                            0
                              1 0  2    0   0
                                                 0 1      0    1
                                                    0        1
                              0 1  5    0
                            B                C
                            B               0 C
                                                 B  0 C   B  2:5 C
                       1    B                C   B C      B    C
                s p ¼ A f p ¼  B  0 0  1  5  0  C           0:5        (8.7)
                      p                          B  0 C ¼ B    C
                            B                C
                                                 @ A      @  0:1  A
                              0 0   0
                            B                C      0
                                                    1       0:5
                            @           5  1 A
                              0 0   0 10    0
             The scaled technology matrix is then obtained using Eq. (8.3). The spe-
          cific result for this example is shown in Eqs. (8.8a), (8.8b). This resulting
          scaled technology matrix clearly shows how materials and services flow
          through the different processes of the system such that a balanced system will
          only have a net output equivalent to the desired functional unit.
                                 0                10                   1
                                   1 0  2    0   0     1   0  0   0   0
                                   0 1  5    0         0 2:5  0   0
                                 B                CB                   C
                                 B               0 CB                 0 C
                                 B                CB                   C

            A p,scaled ¼ A p diag s p ¼  B 0 0  1  5  0  CB  0  0 0:5  0  0  C
                                 B                CB                   C
                                   0 0   0             0   0  0 0:1
                                 B                CB                   C
                                 @           5  1 A@                  0 A
                                   0 0   0 10    0     0   0  0   0 0:5
                                                                      (8.8a)
                                  0                       1
                                    1   0    1     0     0
                                    0 2:5  2:5     0
                                  B                       C
                                  B                      0 C
                                  B                       C
                         A p,scaled ¼  B  0  0  0:5  0:5  0  C        (8.8b)
                                  B                       C
                                    0   0     0
                                  B                       C
                                  @               0:5  0:5 A
                                    0   0     0    1     0
             The equivalent monetary matrix is then obtained using Eq. (8.4),withthe
          results for this example shown in Eqs. (8.9a), (8.9b). This shows the material
          costs and value added into goods and services. The third column of A m,scaled ,
          for example, demonstrates how value is added to the chair which has a value of
          € 12.5 for 0.5 pieces, considering that only electricity (€ 5 for 1 MJ) and wood
          (€ 2.5 for 2.5 kg) amounting to a total of € 7.5 were utilized as input streams.
            A m,scaled ¼ diag αðÞA p,scaled
                      0                 10                        1
                        5 0 0    0    0     1   0    1     0     0
                        0 1 0    0          0 2:5  2:5     0
                      B                 CB                        C
                      B               0 CB                       0 C
                      B                 CB                        C
                    ¼  B  0 0 25  0   0  CB  0  0   0:5  0:5     0  C  (8.9a)
                      B                 CB                        C
                        0 0 0  2            0   0     0
                      B                 CB                        C
                      @               0 A@               0:5  0:5 A
                        0 0 0    0 13:5     0   0     0    1     0
   252   253   254   255   256   257   258   259   260   261   262