Page 161 - Buried Pipe Design
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Design of Gravity Flow Pipes  135

                                              Failure Plane Strength Envelope
                    Soil
                 Unit Weight                           f        f



                                       C                      Mohr’s Circle
               z
                                         f
                  Failure Plane  z  C  z

                          z
                                          f         f
                               x
                                          x
                                                    z
             Trench        z
             (Vertical Cut)         Mohr’s Circle for Critical Stresses at 0
         Figure 3.31 Mohr’s circle analysis for finding critical depth Z for a vertical trench wall
         in a brittle soil cohesion C and a soil friction angle 
, where 2C/( Z)   tan(45°   
/2).




           From tests, Eq. (3.27) provides a reasonable analysis for brittle soil.
         If the soil is plastic, soil slip does not occur until shearing stresses
         reach shearing strength C. Consequently, in plastic soil, the critical
         depth equation is 2C/( Z)   1. Below the water table, critical depth is
         essentially doubled.

           Example Problem 3.5 What is the critical depth  Z of a vertical, opencut,
                                  2
                                              3
           trench wall if C   600 lb/ft ,     120 lb/ft , and 
   30°?
             Substituting into Eq. (3.27) gives Z   17.3 ft. This is a lower limit if the
           soil has some plasticity (is not brittle).
           Example Problem 3.6 Suppose that a sloped trench wall exposes a pipe as
           shown in Fig. 3.30. Pressure P x must be resisted by ring stiffness. What is
           the required pipe stiffness for a 72-in HDPE pipe to prevent buckling?
             Assume the soil is granular with unit weight of 120 pcf. Since there is no
           soil on one side of the pipe, assume the pipe is unsupported and must be
           able to withstand the pressure P x    r.
           From Eq. (3.14),

                                        3EI
                                P cr          3     r
                                           2
                                      (1    ) R
           Assume the following:

                             E   110,000 lb/in 2  
   0.4
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