Page 108 - Calc for the Clueless

Example 22—

The same form

This is the same as the above sketch except that the ''center of the hyperbola," the place where the asymptotes

cross, is no longer (0,0). It is now (-7,6). Transverse vertices: . Foci: . Asymptotes:
.

Example 22 Revisited—

Just like with the ellipse, let's clarify the location of the vertices. In this case, the vertices occur north-south of
the center (-7,6). So the x value of the vertices is the same as the center, x = -7. Substituting, we get

1/2
The vertices are (-7,6 ± 5 ).