Page 81 - Calculus Workbook For Dummies
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                                                   Chapter 5: Getting the Big Picture: Differentiation Basics



                    f Draw a function containing three points where — for three different reasons — you would not
                         be able to determine the slope and thus where you would not be able to find a derivative.
                         Your sketch should contain (1) Any type of gap or discontinuity. There’s no slope and thus no
                         derivative at a gap because you can’t draw a tangent line at a gap (try it). (2) A sharp point or
                         cusp. It’s impossible to draw a tangent line at a cusp because a line touching the function at
                         such a sharp point could rock back and forth. So there’s no slope and no derivative at a cusp.
                         (3) A vertical inflection point. Although you can draw a tangent line at a vertical inflection
                         point, since it’s vertical, its slope — and therefore its derivative — is undefined.
                    g Use the difference quotient to determine the derivative of the line  y =  4 x -  3. y’ = 4.

                                  4 ^  x +  h - - ^h  3  4 x -  3h
                            y = l  lim
                                h "  0     h
                                          3
                                  4 x +  4 h - -  4 x +  3
                              =  lim
                                h "  0    h
                                  4 h
                              =  lim
                                h "  0  h
                              =  lim4
                                h "  0
                            y = l  4
                         You can also figure this out because the slope of  y =  4 x -  3 is 4.
                                                                                         2
                    h Use the difference quotient to find the derivative of the parabola f x =  3 x . f'(x) = 6x
                                                                                  ^ h
                                             2   2
                                           h -
                                      3^ x + h  3 x
                               x =
                            f l ^ h  lim
                                   h "  0  h
                                                  2
                                         2
                                      3 _  x +  2 xh +  h i  -  3 x  2
                                 =  lim
                                   h "  0     h
                                        2
                                                  2
                                      3 x +  6 xh +  3 h -  3 x  2
                                 =  lim
                                   h "  0     h
                                      6 xh +  3 h  2
                                 =  lim        _ Now, factor out the hi
                                   h "  0  h
                                      h 6 +  3 hh
                                         x
                                       ^
                                 =  lim         ^ Cancel the  hh
                                   h "  0  h
                                       x
                                 =  lim 6 +  3 hh  _ Now plug in  0i
                                      ^
                                   h "  0
                                 =  6 x + $
                                       3 0
                               x =
                            f l ^ h  6 x
                                                                                                     2
                    i Use the difference quotient to find the derivative of the parabola from problem 4,  y = -  x +  5.
                         y' = –2x.
                                          2       2
                                        h + - -
                                  -^  x + h  5  _  x +  5i
                            y = l  lim
                                h "  0      h
                                      2
                                                      2
                                               2
                                  -_ x +  2 xh +  h i  +  5 +  x -  5
                              =  lim
                                h "  0       h
                                                    2
                                     2
                                              2
                                  - x -  2 xh -  h + +  x -  5
                                                5
                              =  lim
                                h "  0      h
                                  - 2 xh -  h 2
                              =  lim        ^ Now factorh
                                h "  0  h
                                  h - 2 x -  hh
                                    ^
                              =  lim         ^ And cancelh
                                h "  0  h
                              =  lim - 2 x -  hh
                                  ^
                                h "  0
                             l
                            y = - 2 x
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