Page 43 - Civil Engineering Formulas
P. 43

(approx)
                     (h – d)
           Radius of gyration
                                       t
                                       h
                     + 2b
                  I
                                       +
                                    I
                                      πB
                                        4
                     d 2
                       4
                                       2
                      π
                   b 3 (h – d)
                        b 3 (h – d)
           Moment of inertia and section modulus
                                   h 3
                                                   (b 1 h 1 3  – b 2 h 2 3 ), where
                                  2
                                    3
                                       B
                                         2
                                   +
                                        H –
                   (h 3  – d 3 )+
                        (h 3  + d 3 )+
                                  πBh 2
                                    2
                                        =
                                        h
                                   +
                                   B 2 h
                   b
                        b
                   +
                        +
                                   +
                   d 4
                        d 4
                                  πB 3
                                    16
                                                    105
                       3π
                  3π
                         16
                    16
                                                  64
                                         H + t
                                       2I
                                                   I =
                         6h
                    12
                                    4
                                  t
                  l
                       l
                                        =
                                   I =
                        =
                   I =
                                       I
                                         c
                       I
                         c
                                                       t H  1  1  (B + 2.6t)  b 1  =  t)  (H +  h 1  =  4  2  3I  r =  1  1 (2B + 5.2H)  t  (B – 2.6t)  b 2  =  t)  (H –  h 2  =  4  2  2I  I  =  t  H +  c
                                                   1
                                                               Corrugated sheet iron, B  parabolically curved
                                                    h
                  h
                                        H
                        d
           Section  b      b    B  2  4  B  h  4  B  B  2  h  b 2  b 1
                                  2
                                B
                                           t
                                    18
   38   39   40   41   42   43   44   45   46   47   48