Page 56 - Coulson Richardson's Chemical Engineering Vol.6 Chemical Engineering Design 4th Edition

FUNDAMENTALS OF MATERIAL BALANCES
With 1 per cent loss, polymer entering sub-system
10,000 39
D D 10,101 kg
0.99
Take the next boundary round the reactor system; the feeds to the reactor can then be
calculated.

Short stop
Water
10,101 kg
Reactor
Monomer polymer
Cat.
Recycle
At 90 per cent conversion, monomer feed

10,101
D D 11,223 kg
0.9

Unreacted monomer D 11,223 10,101 D 1122 kg
Short-stop, at 0.5 kg/1000 kg unreacted monomer

D 1122 ð 0.5 ð 10 3 D 0.6kg

Catalyst, at 1 kg/1000 kg monomer

D 11,223 ð 1 ð 10 3 D 11 kg

Let water feed to reactor be F 1 , then for 20 per cent monomer

11,223
0.2 D
F 1 C 11,223
11,223 1 0.2
F 1 D D 44,892 kg
0.2

Now consider filter-dryer sub-system again.
Water in polymer to dryer, at 5 per cent (neglecting polymer loss)

D 10,101 ð 0.05 D 505 kg

Balance over reactor-filter-dryer sub-system gives flows to recovery column.

water, 44,892 C 10,101 505 D 54,448 kg

monomer, unreacted monomer, D 1122 kg