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90  1 / The Foundations: Logic and Proofs


                                                “Proof:" Suppose that n is not positive. Because the conditional statement “If n is positive, then
                                                 2
                                                                                      2
                                                n is positive” is true, we can conclude that n is not positive.

                                                Solution: Let P (n) and Q(n) be as in the solution of Example 16. Then our hypothesis is ¬P (n)
                                                                                    2
                                                and the statement “If n is positive, then n is positive” is the statement ∀n(P (n) → Q(n)).
                                                From the hypothesis ¬P (n) and the statement ∀n(P (n) → Q(n)) we cannot conclude ¬Q(n),
                                                because we are not using a valid rule of inference. Instead, this is an example of the fallacy of
                                                denying the hypothesis. A counterexample is supplied by n =−1, as in Example 16.  ▲



                                                    Finally, we briefly discuss a particularly nasty type of error. Many incorrect arguments are
                                                based on a fallacy called begging the question. This fallacy occurs when one or more steps of
                                                a proof are based on the truth of the statement being proved. In other words, this fallacy arises
                                                when a statement is proved using itself, or a statement equivalent to it. That is why this fallacy
                                                is also called circular reasoning.


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                                EXAMPLE 18      Is the following argument correct? It supposedly shows that n is an even integer whenever n is
                                                an even integer.

                                                                               2
                                                                2
                                                    Suppose that n is even. Then n = 2k for some integer k. Let n = 2l for some integer l.
                                                    This shows that n is even.

                                                Solution: This argument is incorrect. The statement “let n = 2l for some integer l” occurs in
                                                the proof. No argument has been given to show that n can be written as 2l for some integer l.
                                                This is circular reasoning because this statement is equivalent to the statement being proved,
                                                namely, “n is even.” Of course, the result itself is correct; only the method of proof is wrong. ▲



                                                    Making mistakes in proofs is part of the learning process. When you make a mistake that
                                                someone else finds, you should carefully analyze where you went wrong and make sure that
                                                you do not make the same mistake again. Even professional mathematicians make mistakes in
                                                proofs. More than a few incorrect proofs of important results have fooled people for many years
                                                before subtle errors in them were found.


                                                Just a Beginning


                                                We have now developed a basic arsenal of proof methods. In the next section we will introduce
                                                other important proof methods. We will also introduce several important proof techniques in
                                                Chapter 5, including mathematical induction, which can be used to prove results that hold for
                                                all positive integers. In Chapter 6 we will introduce the notion of combinatorial proofs.
                                                    In this section we introduced several methods for proving theorems of the form ∀x(P(x) →
                                                Q(x)), including direct proofs and proofs by contraposition. There are many theorems of this
                                                type whose proofs are easy to construct by directly working through the hypotheses and def-
                                                initions of the terms of the theorem. However, it is often difficult to prove a theorem without
                                                resorting to a clever use of a proof by contraposition or a proof by contradiction, or some
                                                other proof technique. In Section 1.8 we will address proof strategy. We will describe various
                                                approaches that can be used to find proofs when straightforward approaches do not work. Con-
                                                structing proofs is an art that can be learned only through experience, including writing proofs,
                                                having your proofs critiqued, and reading and analyzing other proofs.
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