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6.4 Binomial Coefficients and Identities  417

                                                                                 12 13
                                                     Consequently, the coefficient of x y  in the expansion is obtained when j = 13, namely,

                                                          25  12    13      25!  12 13
                                                             2 (−3)   =−        2 3 .
                                                          13              13! 12!                                                   ▲
                                                        We can prove some useful identities using the binomial theorem, as Corollaries 1, 2, and 3
                                                     demonstrate.


                                  COROLLARY 1         Let n be a nonnegative integer. Then

                                                           n
                                                               n     n
                                                                  = 2 .
                                                               k
                                                         k = 0

                                                     Proof: Using the binomial theorem with x = 1 and y = 1, we see that

                                                                        n                n
                                                                            n                n
                                                         n         n            k n−k
                                                        2 = (1 + 1) =          1 1   =         .
                                                                            k                k
                                                                       k = 0           k = 0
                                                     This is the desired result.
                                                        There is also a nice combinatorial proof of Corollary 1, which we now present.

                                                                                          n
                                                     Proof: A set with n elements has a total of 2 different subsets. Each subset has zero elements,
                                                                                                        n
                                                                                                                                  n

                                                     one element, two elements,..., or n elements in it. There are  0  subsets with zero elements,  1
                                                                                                             n
                                                                           n

                                                     subsets with one element,  subsets with two elements,..., and  subsets with n elements.
                                                                           2                                 n
                                                     Therefore,
                                                         n
                                                             n
                                                             k
                                                        k = 0
                                                     counts the total number of subsets of a set with n elements. By equating the two formulas we
                                                     have for the number of subsets of a set with n elements, we see that
                                                         n
                                                             n      n
                                                                = 2 .
                                                             k
                                                        k = 0
                                  COROLLARY 2         Let n be a positive integer. Then

                                                           n
                                                                 k  n
                                                             (−1)     = 0.
                                                                   k
                                                         k = 0

                                                     Proof: When we use the binomial theorem with x =−1 and y = 1, we see that

                                                                               n                   n
                                                                                   n                   n
                                                             n            n               k n−k               k
                                                        0 = 0 = ((−1) + 1) =          (−1) 1   =         (−1) .
                                                                                   k                   k
                                                                              k = 0               k = 0
                                                     This proves the corollary.
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