Page 110 - Digital Signal and Image Processing Using MATLAB

1

(

f=1/4 (mod 1)

π
M (z = e 2j f )
ρ
f=1/2 ϕ
(mod 1) f=0 (mod 1)

f=−1/4 (mod 1)

M 9

& '
*

"
-
+ %
*> '

+

-

+
6
4%5 = 4%5 +4%5
4 5= 4 5 ! 4 5
% 3

=

+ 2 1
4 5= 4 5 !4 5 '
+
4 '
&
=

+

%

+

+ -
4 5=
4 5 ! 4 5

+
5 > C
+ +

&$

4
&
)
,

+4%5 +4 5 O ,

4%5 4 5 O

!
2

4 5 ! 4 5
J 4 5
4%5 54 J5 + 4 4 5
%

4 5 !4 5 4 J 5

I
! 4 5

+ * 4 % 5 C

J5
J%5
!4 5 ! 4 +4 4 5

C

+ "
9

+4%5 ! 4 5

J4 5

!4 5 ;4 5 !4 5 J
+ , = #4 5 J
J ;4 5

- !4 55
4