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˜
                        This is the general frequency-domain wave equation for E. Using ˜ ¯  −1  we can write (4.200)
                        as
                                                                         −1
                                                      −1
                                                                            ˜
                                                                 ˜ ¯
                                                 ˜
                                                          ¯
                                                                    ˜
                                               jωE = ˜ ¯   · ∇− jωξ · H − ˜ ¯   · J.
                        Substituting this into (4.199) we get
                                     ˜ ¯     −1     ˜ ¯     2             ˜ ¯     −1
                                                                                  ˜
                                                               ˜
                              ¯
                                                                                        ˜
                                                                    ¯
                                              ¯
                              ∇+ jωζ · ˜ ¯   · ∇− jωξ − ω ˜ ¯µ · H = ∇+ jωζ · ˜ ¯   · J − jωJ m .  (4.202)
                                                                         ˜
                        This is the general frequency-domain wave equation for H.
                        Wave equation for a homogeneous, lossy, isotropic medium.    We may specialize
                        (4.201) and (4.202) to the case of a homogeneous, lossy, isotropic medium by setting
                                                    ˜
                                              ¯
                                       ¯
                        ˜ ¯
                            ˜ ¯
                                                           ˜ c
                                                       ˜ i
                        ζ = ξ = 0, ˜ ¯µ = ˜µI, ˜ ¯  = ˜ I, and J = J + J :
                                                          ˜
                                                                             ˜ i
                                                                                 ˜ c
                                                 ˜
                                                                    ˜
                                                       2
                                        ∇× (∇× E) − ω ˜µ˜ E =−∇ × J m − jω ˜µ(J + J ),        (4.203)
                                                                   ˜ i
                                                          ˜
                                                                       ˜ c
                                                       2
                                                 ˜
                                                                               ˜
                                        ∇× (∇× H) − ω ˜µ˜ H =∇ × (J + J ) − jω˜ J m .         (4.204)
                                                              ˜
                                                        ˜ c
                        Using (B.47) and using Ohm’s law J = ˜σE to describe the secondary current, we get
                        from (4.203)
                                           ˜
                                                          ˜
                                                                                     ˜
                                                                    ˜
                                                 2 ˜
                                                                            ˜ i
                                                       2
                                      ∇(∇· E) −∇ E − ω ˜µ˜ E =−∇ × J m − jω ˜µJ − jω ˜µ ˜σE
                                       ˜
                        which, using ∇· E = ˜ρ/˜ , can be simplified to
                                                                          1
                                                2
                                                                      ˜ i
                                                    2 ˜
                                                              ˜
                                             (∇ + k )E =∇ × J m + jω ˜µJ + ∇ ˜ρ.              (4.205)
                                                                          ˜
                                                             ˜
                        This is the vector Helmholtz equation for E. Here k is the complex wavenumber defined
                        through

                                                                       ˜ σ
                                           2    2              2              2  c
                                          k = ω ˜µ˜  − jω ˜µ ˜σ = ω ˜µ ˜  +  = ω ˜µ˜          (4.206)
                                                                      jω
                               c
                        where ˜  is the complex permittivity (4.26).
                          By (4.204) we have
                                                                            ˜ c
                                                                                   ˜
                                                        2
                                                  2 ˜
                                            ˜
                                                            ˜
                                                                    ˜ i
                                      ∇(∇· H) −∇ H − ω ˜µ˜ H =∇ × J +∇ × J − jω˜ J m .
                        Using
                                                        ˜
                                                                                ˜
                                                                  ˜
                                                                            ˜
                                              ˜ c
                                         ∇× J =∇ × ( ˜σE) = ˜σ∇× E = ˜σ(− jωB − J m )
                               ˜
                        and ∇· H = ˜ρ m / ˜µ we then get
                                                                           1
                                              2   2 ˜         ˜ i    c ˜
                                            (∇ + k )H =−∇ × J + jω˜  J m +  ∇ ˜ρ m ,          (4.207)
                                                                           ˜ µ
                                                              ˜
                        which is the vector Helmholtz equation for H.
                        4.11.2   Field relationships and the wave equation for two-dimensional
                                 fields
                          Many important canonical problems are two-dimensional in nature, with the sources
                        and fields invariant along one direction. Two-dimensional fields have a simple structure
                        © 2001 by CRC Press LLC
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