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eigenvalues is an eigenfunction of a one-dimensional Sturm–Liouville problem. For the
                        three-dimensional problem, an eigenfunction

                                                                                 z)
                                          ψ mnp (x, y, z) = A mnp sin(k x m  x) sin(k y n  y) sin(k z p
                        is associated with each three-dimensional eigenvalue k mnp . Each choice of m, n, p pro-
                        duces a discrete cavity resonance frequency at which the boundary conditions can be
                        satisfied. Depending on the values of L 1,2,3 , we may have more than one eigenfunction
                        associated with an eigenvalue. For example, if L 1 = L 2 = L 3 = L then k 121 = k 211 =
                              √
                        k 112 =  6π/L. However, the eigenfunctions associated with this single eigenvalue are all
                        different:
                                                                          z),
                                               ψ 121 = sin(k x 1  x) sin(k y 2  y) sin(k z 1
                                                                          z),
                                               ψ 211 = sin(k x 2  x) sin(k y 1  y) sin(k z 1
                                                                          z).
                                               ψ 112 = sin(k x 1  x) sin(k y 1  y) sin(k z 2
                        When more than one cavity mode corresponds to a given resonant frequency, we call the
                        modes degenerate. By completeness, we can represent any well-behaved function as

                                         f (x, y, z) =  A mnp sin(k x m  x) sin(k y n  y) sin(k z p z).
                                                    m,n,p
                        The A mnp are found using orthogonality. When such expansions are used to solve prob-
                        lems involving objects (such as excitation probes) inside the cavity, they are termed
                        normal mode expansions of the cavity field.
                        Solutions in cylindrical coordinates.  In cylindrical coordinates the Helmholtz equa-
                        tion is
                                                                 2
                                                   2
                           1 ∂     ∂ψ(ρ, φ, z)     1 ∂ ψ(ρ, φ, z)  ∂ ψ(ρ, φ, z)  2
                                ρ            +               +             + k ψ(ρ, φ, z) = 0.  (A.117)
                           ρ ∂ρ       ∂ρ        ρ 2   ∂φ 2         ∂z 2
                        With ψ(ρ, φ, z) = P(ρ)#(φ)Z(z) we obtain
                                                                    2
                                                         2
                                   1 ∂     ∂(P#Z)     1 ∂ (P#Z)    ∂ (P#Z)    2
                                        ρ          +            +          + k (P#Z) = 0;
                                   ρ ∂ρ     ∂ρ       ρ 2  ∂φ 2       ∂z 2
                        carrying out the ρ derivatives and dividing through by P#Z we have
                                                              2
                                                                               2
                                               2
                                            1 d Z    2    1 d #     1 dP    1 d P
                                          −       = k +          +        +       .
                                            Z dz 2      ρ # dφ  2  ρP dρ    P dρ  2
                                                          2
                        The left side depends on z while the right side depends on ρ and φ, hence both must
                                               2
                        equal the same constant k :
                                              z
                                                             2
                                                          1 d Z    2
                                                        −     2  = k ,                        (A.118)
                                                                   z
                                                          Z dz
                                                                        2
                                                      2
                                                   1 d #     1 dP    1 d P
                                              2                               2
                                             k +          +       +        = k .              (A.119)
                                                                              z
                                                  2
                                                 ρ # dφ 2   ρP dρ    P dρ 2
                        We have separated the z-dependence from the dependence on the other variables. For
                        the harmonic equation (A.118),

                                                     A z sin k z z + B z cos k z z,  k z  = 0,
                                             Z(z) =                                           (A.120)
                                                     a z z + b z ,       k z = 0.
                        © 2001 by CRC Press LLC
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