Page 108 - Elements of Chemical Reaction Engineering 3rd Edition
P. 108

80                                  Rate Laws and Stoichiometry   Chap. 3

                        Comparing  Equations  (3-16)  and  (3-17),  we  see the relationship  between  the
                        specific  reaction  rate  with  respect  to  diphenyl  and  the  specific  reaction  rate
                        with respect to benzene is







                          Example 3-3  Formulating a Reversible Rate Law

                          The exothermic reaction
                                                   Af2B  ___)  2D                   (E3-3.1)

                          is virtually irreversible at low temperatures and the rate law is

                                                    -rA = k,Cy2CB                   (E3-3.2)
                          Suggest a rate law  that  is valid  at high  temperatures, where the reaction  is revers-
                          ible:
                                                  A+2B e                            (E3-3.3)
                                                               2D


                          Solution
        These criteria must   The rate law for the reversible reaction must
              be satisfied
                             1.  satisfy thermodynamic relationships at equilibrium, and
                             2.  reduce to the irreversible rate law when the concentration of one or more of
                               the reaction products is zero.

                          We  know  from  thermodynamics  that  the  equilibrium  relationship  for  Reaction
                          (E3-3.1) as written is
                                                c2,                   dm3
                                          Kc= -                 [K,]  =            (E3-3.4)
                                                      with units
                                               cAecie
                          Rearranging Equation (E3-3.4) in  the form\





                          suggests that we try a reversible rate law of  the form
                                                 -r,  = k, [ CACi - g]             (E3-3.5)




                          Equation (E3-3.5)  satisfies the equilibrium conditions but  does not  simplify to the
                          initial, irreversible rate when  C,  = 0. Substituting C,  = 0 into the equation being
                          tested yields
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