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                            120                        Moments and Cumulants

                            where the sum is over all nonnegative integers x 1 , x 2 ,..., x m summing to n. Writing
                                                                    n                   x j
                                       m                m            m
                                                  x j                      exp(t j )θ j
                                         exp(t j x j )θ  =                              ,
                                                  j       exp(t j )θ j     m
                                       j=1             j=1          j=1    j=1  exp(t j )θ j
                            it follows from the properties of the multinomial distribution that the moment-generating
                            function of X is
                                                       n               n
                                            m                m

                                                                                           m
                                  M X (t) =   exp(t j )θ j  =  exp(t j )θ j  , t = (t 1 ,..., t m ) ∈ R .
                                            j=1             j=1
                              The cumulant-generating function is therefore given by

                                                                 m

                                                   K X (t) = n log  exp(t j )θ j .
                                                                j=1
                            It follows that, for j = 1,..., m,
                                               E(X j ) = nθ j ,  Var(X j ) = nθ j (1 − θ j )

                            and, for j, k = 1,..., m,
                                                      Cov(X j , X k ) =−nθ j θ k .
                            Thus, the covariance matrix of X is the m × m matrix with ( j, k)th element given by
                                                         nθ j (1 − θ j )if j = k

                                                   σ jk =                   .
                                                         −nθ j θ k   if j 
= k



                                         4.5 Moments and Cumulants of the Sample Mean
                            Let X 1 , X 2 ,..., X n denote independent, identically distributed, real-valued random vari-
                            ables. Let
                                                                 n
                                                               1
                                                          ¯
                                                          X n =     X j
                                                               n
                                                                 j=1
                            denote the sample mean based on X 1 , X 2 ,..., X n .
                                                                             ¯
                              In this section, we consider the moments and cumulants of X n . First consider the cumu-
                                                                                    ¯
                                                                              ¯
                            lants. Let κ 1 ,κ 2 ,... denote the cumulants of X 1 and let κ 1 (X n ),κ 2 (X n ),... denote the
                                       ¯
                            cumulants of X n . Using Theorems 4.14 and 4.15, it follows that
                                                            1
                                                     ¯
                                                  κ j (X n ) =  j−1  κ j ,  j = 1, 2,....       (4.4)
                                                          n
                            For convenience, here we are assuming that all cumulants of X 1 exist; however, it is clear
                            that the results only require existence of the cumulants up to a given order. For instance,
                               ¯
                            κ 2 (X n ) = κ 2 /n holds only provided that κ 2 exists.
                                                             ¯
                              To obtain results for the moments of X n ,we can use the expressions relating moments
                            and cumulants; see Lemma 4.1. Then
                                                               2     n − 1      1
                                                                             2
                                          ¯
                                       E(X n ) = E(X 1 ) and E X ¯  =   E(X 1 ) +  E X 2  .
                                                              n                      1
                                                                     n          n
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