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244    12. Endomorphisms of Elliptic Curves

        (4.13) ImaginaryQuadratic Fields with Class Number 1.

               √                √                        √
                                                                  2
        K = Q( −1)        R = Z[ −1]             j(τ) = j( −1) = (2 · 3) 3
                                 √                        √
                         R 2 = Z[2 −1]               = j(2 −1) = (2 · 3 · 11) 3
               √                √                        √        2   3
          = Q( −2)        R = Z[ −2]                 = j( −2) = (2 · 5)
                                      √                        √
               √                 −1 +  −3                 −1 +   −3
          = Q( −3)        R = Z                      = j             = 0
                                     2                        2
                                √                        √
                                                                     3
                                                                 4
                         R 2 = Z[ −3]                = j( −3) = 2 · 3 · 5 3
                                       √                        √

                                 −1 + 3 −3                −3 + 3 −3
                         R 3 = Z                     = j
                                     2                         2
                                                     =−2 15  · 3 · 5 3
                                      √                        √

               √                 −1 +  −7                 −1 +   −7
          = Q( −7)        R = Z                      = j
                                     2                        2
                                                     =−(3 · 5) 3
                                √                        √
                         R 2 = Z[ −7]                = j( −7) = (3 · 5 · 17) 3
                                      √                        √
               √                 −1 +  −11                −1 +   −11
          = Q( −11)       R = Z                      = j
                                     2                         2
                                                          5 3
                                                     =−(2 )
                                      √                        √

               √                 −1 +  −19                −1 +   −19
          = Q( −19)       R = Z                      = j
                                     2                         2
                                                          5
                                                     =−(2 · 3) 3
                                      √                        √

               √                 −1 +  −43                −1 +   −43
          = Q( −43)       R = Z                      = j
                                     2                         2
                                                          6
                                                     =−(2 · 3 · 5) 3
                                      √                        √
               √                 −1 +  −67                −1 +   −67
          = Q( −67)       R = Z                      = j
                                     2                         2
                                                          5
                                                     =−(2 · 3 · 5 · 11) 3
                                      √                        √
               √                 −1 +  −163               −1 +   −163
          = Q( −163)      R = Z                      = j
                                      2                        2
                                                          6
                                                     =−(2 · 3 · 5 · 23 · 29) 3
                                         √
        (4.14) Remark. The class number of Q( −23) is three and
                              √

                         −1 +  −23        12 3      3       3
                      j              =−α 5 (2α − 1) (3α + 2) ,
                             2
               3
        where α − α − 1 = 0
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