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50     2. Plane Algebraic Curves

        Exercises
                                 d
         1. Show that the dimension of H is the binomial coefficient    n+d     − 1.
                                 n
                                                        n
         2. If P 1 , P 2 ,and P 3 are three points in P 2 not on a line, then show that the set of conics
            through P 1 , P 2 ,and P 3 form a two-dimensional subspace of the five-dimensional space
             2
            H of conics in P 2 . Show that the set S of conics through 1 : 0 : 0, 0 : 1 : 0, and 0 : 0 : 1
             2
            can be parametrized by the coefficiens a : b : c of the equations axy + bwy + cwx = 0.



            Describe the subfamilies of S consisting of conics which also go through w : x : y and


            which also go through two distinct points w : x : y and w : x : y .




        §3. Elements of Intersection Theory for Plane Curves
        The following result gives some indication of the number of intersection points be-
        tween two plane curves.
        (3.1) Proposition. Let C f and C g be two plane algebraic curves of degrees m and
        n, respectively, defined over k. If for some extension K of k the set C f (K) ∩ C g (K)
        has strictly more than mn points, then C f and C g have an entire curve in common.
        Proof. Suppose C f (K) ∩ C g (K) contains mn + 1 points. Join these points by lines
        and with a projective tranformation move the two curves so that the point (0, 0, 1) is
        not on any of these lines. Decompose the polynomials f and g with respect to the
        variable y:
                                       m
                         f (w, x, y) = a 0 y + a 1 y m−1  + ··· + a m ,
                                       m
                         g(w, x, y) = b 0 y + b 1 y n−1  +· · · + b n ,
        where a i (w, x) and b j (w, x) are homogeneous of degrees i and j, respectively. By
        (4.3) of the Appendix the resultant R( f, g)(w, x) is homogeneous of degree mn.
        Moreover, R( f, g)(w, x) = 0 for w, x ∈ K if and only if there exists y in K such
        that w : x : y ∈ C f (C) ∩ C g (K). Since there exists mn + 1 points (w i , x i , y i ) in
        C f (K) ∩ C g (K) for i = 0,... , mn, it follows that the polynomial

                                       (x i w − w i x)
                                  0≤i≤mn
        of degree mn + 1 divides the polynomial R( f, g)(w, x) of degree mn. From this
        we deduce that R( f, g) = 0, and, hence, f and g have a common factor h. Then
        C h ⊂ C f ∩ C g , and this proves the theorem.
           The above theorem is a corollary of Bezout’s theorem which says that over an
        algebraically closed field the intersection of a plane curve of degree m with a plane
        curve of degree n will have exactly mn points in common when the intersection mul-
        tiplicity is assigned to each intersection point, or the two curves will have a common
        subcurve. This is a more difficult result and requires both an analysis of singular
        points and a good definition of intersection multiplicity.
                                       d
           In (2.5) we described the space H (k) of hypersurfaces of degree d over k in
                                       n
        P n . For two plane curves C f and C f of degree d over k we can speak of the line
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