Page 268 - Engineering Electromagnetics, 8th Edition
P. 268

250                ENGINEERING ELECTROMAGNETICS

                                     With the help of Stokes’ theorem, we may therefore transform (21), (26), and (22)
                                     into the equivalent curl relationships:

                                                                 ∇× M = J B
                                                                     B
                                                                 ∇×     = J T
                                                                     µ 0

                                                                  ∇× H = J                           (27)

                                        We will emphasize only (26) and (27), the two expressions involving the free
                                     charge, in the work that follows.
                                        The relationship between B, H, and M expressed by (25) may be simplified for
                                     linear isotropic media where a magnetic susceptibility χ m can be defined:

                                                                  M = χ m H                          (28)

                                     Thus we have

                                                               B = µ 0 (H + χ m H)
                                                                 = µ 0 µ r H
                                     where

                                                                 µ r = 1 + χ m                       (29)
                                     is defined as the relative permeability µ r .Wenext define the permeability µ:
                                                                                                     (30)
                                                                  µ = µ 0 µ r
                                     and this enables us to write the simple relationship between B and H,
                                                                   B = µH                            (31)


                   EXAMPLE 8.5
                                     Given a ferrite material that we shall specify to be operating in a linear mode with
                                     B = 0.05 T, let us assume µ r = 50, and calculate values for χ m , M, and H.
                                     Solution. Because µ r = 1 + χ m ,wehave

                                                               χ m = µ r − 1 = 49
                                     Also,
                                                                 B = µ r µ 0 H

                                     and
                                                                  0.05
                                                         H =               = 796 A/m
                                                             50 × 4π × 10 −7
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