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8                                Entropy Analysis in Thermal Engineering Systems


             To alter the entropy of a system would yield a change in the entropy of its
          immediate surrounding. Let us consider the second example of Section 1.5.
          The amount of heat required to increase the temperature of water from 20°
          Cto60°Cis Q¼mc p ΔT¼(1)(4.18)(60 20)¼167.2 kJ. Suppose this
          amount of heat is supplied from a condensing steam at 100°C. Given the
          evaporation enthalpy of 2256kJ/kg for water at 100°C, about 0.074kg
          steam should be condensed to provide 167.2kJ heat.
             The change in the entropy of the condensing steam at the constant tem-
          perature of 100°C is calculated as follows.
                                          167:2
                        ΔS steam ¼ S 2  S 1 ¼   ¼ 0:448 kJ=K
                                         373:15
          The negative sign indicates that the heat is extracted from the steam. Thus,
          the change in the entropy of the steam is also negative.
             If we now consider the net entropy change (of the system and its sur-
          rounding), we find

                   ΔS net ¼ ΔS water + ΔS steam ¼ 0:535 0:448 ¼ 0:087kJ=K
          That is, the process of heating water from 20°Cto60°C where the source of
          heat is the steam condensing at 100°C leads to a net increase of 0.087kJ/K in
          entropy. This net entropy increase is referred to as the entropy generation.

          1.7.1 Entropy generation in closed systems

          The relation for the entropy generation of a system with a fixed mass can
          now be presented by generalization of the example that we just discussed
          above.
                                                                      (1.12)
                                Φ ¼ ΔS system + ΔS surrounding
          where the change in the entropies of the system and the surrounding can be
          evaluated using Eq. (1.10). If the system receives heat from its surrounding,
          the first term on the right-hand side of Eq. (1.12) yields a positive value,
          whereas the second term leads to a negative value. Conversely, if the system
          loses heat to its surrounding, the first term yields a negative value and the
          second term leads to a positive value. In either case, Eq. (1.12) will always
          have a positive quantity.
             Eq. (1.12) may be expressed in alternative forms depending on whether
          the temperature of the system or surrounding is constant. For example, if
          the system receives an amount of heat Q from a heat source (the surrounding)
          maintained at a constant temperature, the entropy generation is determined as
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