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Appendices                                                   191


                                  "                                !        !#
                                                            n + a j ξ
                       k                                     i
                     X                        0
              G ξðÞ ¼     n + a j ξ  h j TðÞ T s s + s T, j  R ln  j   R lnp
               f
                           i
               m           j                  j              n + aξ
                                                              i
                      j¼1
                                                                          (C.4)
              At the minimum G m , one must solve dG m /dξ¼0 to get
                               f
                                                 f
                  (                                       !            )
                                                    n + a j ξ  a j
                k     h                  i           i
                                  0                  j
               X
                                          + T s R ln                  a j  ¼ 0
                    a j h j TðÞ T s s + s T, j
                                  j                 n + aξ   + T s R lnp
                                                     i
               j¼1
                                                                          (C.5)
              Upon simplification and rearrangement, we obtain
                         !       (                                          )
              Y n + a j ξ  a j        1  X n    h                  io
                    i
               k
                                           k
                    j                                       0
                            ¼ exp
                   n + aξ                     a j h j TðÞ T s s + s T, j   a lnp
                                                            j
                    i
              j¼1                    T s R  j¼1
                                                                          (C.6)
              For a reactive system with a known initial state and composition that inter-
              acts with its surrounding that is at temperature T s , the only unknown in
              Eq. (C.6) is ξ.If ξ at minimum G m happens to be close to ξ eq (as was seen
                                           f
              in Fig. 10.6) the composition of the mixture at the final state may then be
              readily obtained from Eq. (C.3) and using ξ determined from Eq. (C.6).
              Reference
              [1] J.H. Cotterill, The Steam Engine Considered as a Thermodynamic Machine, A Treatise
                on the Thermodynamic Efficiency of Steam Engines, second ed., E & F. N. Spon,
                London, 1890.
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