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book   Mobk070    March 22, 2007  11:7








                     6  ESSENTIALS OF APPLIED MATHEMATICS FOR SCIENTISTS AND ENGINEERS
























                       FIGURE 1.3: An element in spherical coordinates


                       Dividing through by the volume, we find after using Fourier’s law for the heat fluxes


                                                                                   2
                                                                                        2
                                                                              2
                                                                      2
                                                                         2
                                   ρc ∂u/∂t = (1/r)∂(r∂u/∂r)/∂r + (1/r )∂ u/∂θ + ∂ u/∂z + q         (1.11)
                       1.3.3  Spherical Coordinates
                       An element in a spherical coordinate system is shown in Fig. 1.3. The volume of the element is
                                           2
                       r sin θ   rr θ = r sin θ r θ  . The net heat flows out of the element in the r, θ,and
                         directions are respectfully

                                                           r 2
                                                         q r sin θ θ                                (1.12)
                                                           θ
                                                         q r sin θ r                                (1.13)

                                                         q r θ r                                    (1.14)

                       It is left as an exercise for the student to show that


                                                                               2
                                                                            2
                                                                                    2
                                                              2
                                                      2
                                      ρc ∂u/∂t = k[(1/r )∂/∂r(r ∂u/∂r) + (1/r sin θ)∂ u/∂  2
                                                       2
                                                + (1/r sin θ)∂(sin θ∂u/∂θ)/∂θ + q                   (1.15)
                       The Laplacian Operator
                       The linear operator on the right-hand side of the heat equation is often referred to as the
                                                         2
                       Laplacian operator and is written as ∇ .
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