Page 177 - Foundations Of Differential Calculus
P. 177

160    8. On the Higher Differentiation of Differential Formulas
          II. Let the given expression be

                                        2     2
                                      dx + dy  ,
                                          2
                                         d x
             in which dy is assumed to be constant. We let dy = pdx and dp = qdx,
                                                 2
             so that the expression becomes −p 1+ p /q, as in paragraph 270.
             Since
                                                          2
                                                  2
                             dy               dx d y − dy d x
                         p =       and    q =               ,
                             dx                    dx 3
             we obtain the expression
                                          2    2
                                    dy dx + dy
                                               2
                                       2
                                    dy d x − dx d y .
             Here no differential is assumed constant, and this expression has the
             same value as the one originally proposed.
         III. Let the given expression be

                                       2
                                              2
                                     yd x − xd y
                                                ,
                                        dx dy
             in which the differential ydx is assumed to be constant. We let dy =
             pdx, dp = qdx, and as we saw in paragraph 270, this expression is
             transformed into
                                         xq   xp
                                    −1 −    +    .
                                          p    y
             When we do not assume any differential to be constant, the expression
             is transformed into
                            2        2
                       xdxd y − xdy d x   xdy
                 − 1 −                  +
                               2
                            dx dy         ydx
                                                              2
                                  2
                                                    2
                                        2
                            xdxdy − ydx dy − yx dx d y + yx dy d x
                         =                                       .
                                              2
                                           ydx dy
         IV. Let the given expression be
                                        2
                                      dx + dy2 ,
                                          2
                                         d y
                                                       2

             in which we assume that the differential  dx + dy 2  is constant.
             When we let dy = pdx and dp = qdx, there arises the expression
                  2    2
              1+ p   /q as in paragraph 270. Now we set p = dy/dx and
                                         2
                                                 2
                                      dx d y − dy d x
                                  q =
                                           dx 3
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